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Roman55 [17]
2 years ago
12

Convert the repeating nonterminating 0.1515...

Mathematics
1 answer:
solniwko [45]2 years ago
5 0
303/2000 is the answer to your question
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70 points!
astra-53 [7]

y = 4.5x

Explanation:

9 ÷ 2 = 4.5

18 ÷ 4 = 4.5

27 ÷ 6 = 4.5

3 0
3 years ago
Which diagram best shows how fraction bars can be used to evaluate 1/2 divided by 1/4?
Helga [31]

Answer:

the second one

Step-by-step explanation:

2 halves make a whole. 1/2 + 1/2

4 fourths make a whole. 1/4 + 1/4 + 1/4 + 1/4

a half of a fourth is an eighth. 1/4 ÷ 1/2 = 1/8

3 0
2 years ago
a groups of 210 children attended a school picnic. only 60 of the children ate. what fraction of the children ate?
Amiraneli [1.4K]
The answer is 60/210.
I hope I'm right
Brainliest please!
5 0
3 years ago
Read 2 more answers
Find the smallest 4 digit number such that when divided by 35, 42 or 63 remainder is always 5
alex41 [277]

The smallest such number is 1055.

We want to find x such that

\begin{cases}x\equiv5\pmod{35}\\x\equiv5\pmod{42}\\x\equiv5\pmod{63}\end{cases}

The moduli are not coprime, so we expand the system as follows in preparation for using the Chinese remainder theorem.

x\equiv5\pmod{35}\implies\begin{cases}x\equiv5\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{42}\implies\begin{cases}x\equiv5\equiv1\pmod2\\x\equiv5\equiv2\pmod3\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{63}\implies\begin{cases}x\equiv5\equiv2\pmod 3\\x\equiv5\pmod7\end{cases}

Taking everything together, we end up with the system

\begin{cases}x\equiv1\pmod2\\x\equiv2\pmod3\\x\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

Now the moduli are coprime and we can apply the CRT.

We start with

x=3\cdot5\cdot7+2\cdot5\cdot7+2\cdot3\cdot7+2\cdot3\cdot5

Then taken modulo 2, 3, 5, and 7, all but the first, second, third, or last (respectively) terms will vanish.

Taken modulo 2, we end up with

x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod2

which means the first term is fine and doesn't require adjustment.

Taken modulo 3, we have

x\equiv2\cdot5\cdot7\equiv70\equiv1\pmod3

We want a remainder of 2, so we just need to multiply the second term by 2.

Taken modulo 5, we have

x\equiv2\cdot3\cdot7\equiv42\equiv2\pmod5

We want a remainder of 0, so we can just multiply this term by 0.

Taken modulo 7, we have

x\equiv2\cdot3\cdot5\equiv30\equiv2\pmod7

We want a remainder of 5, so we multiply by the inverse of 2 modulo 7, then by 5. Since 2\cdot4\equiv8\equiv1\pmod7, the inverse of 2 is 4.

So, we have to adjust x to

x=3\cdot5\cdot7+2^2\cdot5\cdot7+0+2^3\cdot3\cdot5^2=845

and from the CRT we find

x\equiv845\pmod2\cdot3\cdot5\cdot7\implies x\equiv5\pmod{210}

so that the general solution x=210n+5 for all integers n.

We want a 4 digit solution, so we want

210n+5\ge1000\implies210n\ge995\implies n\ge\dfrac{995}{210}\approx4.7\implies n=5

which gives x=210\cdot5+5=1055.

5 0
2 years ago
What is 45/117 as a simplified fraction
qaws [65]
5/13
45÷9=5
117÷9=13..

6 0
3 years ago
Read 2 more answers
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