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snow_tiger [21]
4 years ago
14

Write these decimals in order from least to greatest on the chart. If two decimals are equivalent, record the equivalent decimal

s on the same row. 5.42, 5.04, 5.24, 5.2, 5.042, 5.402, 5.240, 5.20, 5.204, 5.024, 5.420, 5.4, 5.02, 5.40
Mathematics
1 answer:
umka2103 [35]4 years ago
3 0

5.02 \:5.024 \: 5.04 \: 5.042
5.2 \: 5.2 \: 5.204 \: 5.24 \: 5.24
5.402 \: 5.4 \: 5.4 \: 5.42 \: 5.42
i think im right but not sure
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Please help thank you.
MA_775_DIABLO [31]
Question 1:

To start off this question, we can tell that this is a square because it has 4 right angles and 4 congruent sides.

A square has four parallel sides and 4 congruent sides, so a square is a rhombus and parallelogram. 

A square has 4 right angles, so it's also a rectangle.

A square has 4 sides, so it's also a quadrilateral.

The first choice is your answer.

Question 2:

Not all quadrilaterals are rectangles, so A is incorrect.

Not all quadrilaterals are squares, so B is incorrect.

All rectangles are types of quadrilaterals, so C is correct.

Not all quadrilaterals are parallelograms, so D is incorrect.

Thus, C is your answer.

Question 3: 

The first choice will not work because a rhombus will satisfy those conditions, and a rhombus is not always a square.

The second choice will work because only a square will satisfy that condition because only squares have 4 congruent sides along with equal diagonals.

Thus, the second choice is your answer.

Have an awesome day! :)
7 0
4 years ago
I really need help here ASAP​
AlexFokin [52]

Answer:

D. x=\frac{-4-\sqrt{31}}{3} or  x=\frac{-4+\sqrt{31}}{3}

Step-by-step explanation:

The given equation is:

3x^2+8x=5

Divide through by 3;

x^2+\frac{8}{3}x=\frac{5}{3}

Add the square of half the coefficient of x to both sides.

x^2+\frac{8}{3}x+(\frac{4}{3})^2=\frac{5}{3}++(\frac{4}{3})^2

x^2+\frac{8}{3}x+\frac{16}{9}=\frac{5}{3}+\frac{16}{9}

The left hand side is now a perfect square:

(x+\frac{4}{3})^2=\frac{31}{9}

Take square root

x+\frac{4}{3}=\pm \sqrt{ \frac{31}{9}}

x=-\frac{4}{3}\pm \sqrt{ \frac{31}{9}}

x=-\frac{4}{3}\pm \frac{\sqrt{31}}{3}

D. x=\frac{-4-\sqrt{31}}{3} or  x=\frac{-4+\sqrt{31}}{3}

5 0
3 years ago
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