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3 years ago

What is the degree of the equation?

Mathematics

2 answers:

wolverine [178]3 years ago

4 0

Answer:

1 (give brainliest plss)

Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant 5 • -8 = -40

Step-2 : Find two factors of -40 whose sum equals the coefficient of the middle term, which is -3 .

-40 + 1 = -39

-20 + 2 = -18

-10 + 4 = -6

-8 + 5 = -3 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and 5

5x2 - 8x + 5x - 8

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (5x-8)

Add up the last 2 terms, pulling out common factors :

1 • (5x-8)

Step-5 : Add up the four terms of step 4 :

(x+1) • (5x-8)

Which is the desired factorization

Varvara68 [4.7K]3 years ago

4 0

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the concept of Quadratic Equations.

Degree of a equation represents the highest power of the varible in the equation, For quadratic equation the degree is 2.

Leading Coefficient are the constant numbers that are significantly multiplied with the variables in the equation.

==> 5x^2 - 3x - 8 = 0

==> 5x^2 -8x +5x -8=0

==> x(5x-8) +1(5x-8)=0

==> (5x-8)(x+1) = 0

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Given any 2 point P(m,n) and Q(k,l),

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thus the coordinates of points $M_{JK}, M_{KL}, M_{LM}, M_{JM},$

are as follows:

$M_{JK}= (\frac{-3+1}{2}, \frac{1+3}{2})=(-1,2), \\\\M_{KL}= (\frac{1+5}{2}, \frac{3-1}{2}=(3,1), \\\\M_{LM}= (\frac{5-1}{2}, \frac{-1-3}{2})=(2, -2),\\\\ M_{JM}= (\frac{-3-1}{2}, \frac{1-3}{2})=(-2,-1)$

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The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:

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}$

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thus the distances connecting the opposite entrances can be calculated as follows:

$|M_{JK},M_{LM}|= \sqrt{ (-1-2)^{2} + (2-(-2))^{2} }= \sqrt{9+16}=5$

$|M_{KL}M_{JM}|= \sqrt{ (3-(-2))^{2} + (1-(-1))^{2}}= \sqrt{25+4}= \sqrt{29}=5.39$

Thus the total distance of the paths joining the opposite entrances is

5+5.39 units = 50 m + 53.9 m = 104 m (rounded to the nearest meter)

Answer: 104 m

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