Answer:
a) The interval for those who want to go out earlier is between 43.008 and 46.592
b) The interval for those who want to go out later is between 47.9232 and 51.9168
Step-by-step explanation:
Given that:
Sample size (n) =128,
Margin of error (e) = ±4% =
a) The probability of those who wanted to get out earlier (p) = 35% = 0.35
The mean of the distribution (μ) = np = 128 * 0.35 = 44.8
The margin of error = ± 4% of 448 = 0.04 × 44.8 = ± 1.792
The interval = μ ± e = 44.8 ± 1.792 = (43.008, 46.592)
b) The probability of those who wanted to start school get out later (p) = 39% = 0.39
The mean of the distribution (μ) = np = 128 * 0.39 = 49.92
The margin of error = ± 4% of 448 = 0.04 × 49.92 = ± 1.9968
The interval = μ ± e = 44.8 ± 1.792 = (47.9232, 51.9168)
The way for those who want to go out earlier to win if the vote is counted is if those who do not have any opinion vote that they want to go earlier
Answer:
53, 54, 55
Step-by-step explanation:
The average of the three is the middle one. The average is the sum, divided by 3: 162/3 = 54.
The three integers are 53, 54, 55.
Answer: The required probability is 
Step-by-step explanation: Given that an urn contains 6 red marbles and 4 black marbles. Two marbles are randomly drawn one by one from the urn without replacement.
We are to find the probability that both drawn marbles are black.
Let E and F denote the events of two marbles one by one without replacement and let S and S' denote the corresponding sample spaces.
Then, we have
Therefore, the probability that both marbles are red is given by
Thus, the required probability is
7/3-<span>1.41
7/1.59
4.4
That's what i got...
</span>
It's A (x+3)(x+3). Once you factor the equation you get the following answer.
