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Nuetrik [128]
3 years ago
11

What property is this? (3x+12y)+(10x-5y)

Mathematics
1 answer:
SpyIntel [72]3 years ago
6 0

Answer:

Assciates Property

Step-by-step explanation:

look at the picture above

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WILL GIVE BRAINLIEST AND 100 POINTS
ICE Princess25 [194]

Answer:

a) The interval for those who want to go out earlier is between 43.008 and 46.592

b) The interval for those who want to go out later is between 47.9232 and 51.9168

Step-by-step explanation:

Given that:

Sample size (n) =128,

Margin of error (e) = ±4% =

a) The probability of those who wanted to get out earlier (p) = 35% = 0.35

The mean of the distribution (μ) = np = 128 * 0.35 = 44.8

The margin of error = ± 4% of 448 = 0.04 × 44.8 =  ± 1.792

The interval = μ ± e = 44.8 ± 1.792 = (43.008, 46.592)

b) The probability of those who wanted to start school get out later (p) = 39% = 0.39

The mean of the distribution (μ) = np = 128 * 0.39 = 49.92

The margin of error = ± 4% of 448 = 0.04 × 49.92 =  ± 1.9968

The interval = μ ± e = 44.8 ± 1.792 = (47.9232, 51.9168)

The way for those who want to go out earlier to win if the vote is counted is if those who do not have any opinion vote that they want to go earlier

4 0
3 years ago
The sum of three consecutive integers is 162. What are the​ integers?
Paha777 [63]

Answer:

  53, 54, 55

Step-by-step explanation:

The average of the three is the middle one. The average is the sum, divided by 3: 162/3 = 54.

The three integers are 53, 54, 55.

4 0
3 years ago
An urn contains 6 red marbles and 4 black marbles. Two marbles are randomly drawn (one by one) from the urn without replacement.
strojnjashka [21]

Answer:   The required probability is \dfrac{2}{15}.

Step-by-step explanation:  Given that an  urn contains 6 red marbles and 4 black marbles. Two marbles are randomly drawn one by one from the urn without replacement.

We are to find the probability that both drawn marbles are black.

Let E and F denote the events of two marbles one by one without replacement and let S and S' denote the corresponding sample spaces.

Then, we have

n(E)=^4C_1=4,\\\\n(F)=^3C_1=3,\\\\n(S)=^{10}C_1=10,\\\\n(S')=^9C_1=9.

Therefore, the probability  that both marbles are red is given by

p=P(E)\times P(F)=\dfrac{n(E)}{n(S)}\times\dfrac{n(F)}{n(S')}=\dfrac{4}{10}\times\dfrac{3}{9}=\dfrac{2}{15}.

Thus, the required probability is \dfrac{2}{15}.

4 0
3 years ago
In an algebra 2 test and I'm stumped
quester [9]
7/3-<span>1.41
7/1.59
4.4
That's what i got...

</span>
3 0
4 years ago
Read 2 more answers
Help me please anyone ? No guessing
lawyer [7]

It's A (x+3)(x+3). Once you factor the equation you get the following answer.

6 0
4 years ago
Read 2 more answers
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