Answer:
22.38 g of silicone-32 will be present in 300 years.
Step-by-step explanation:
A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by
![N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}](https://tex.z-dn.net/?f=N%28t%29%3DN_0%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7B%5Cfrac%7Bt%7D%7Bt_%7B1%2F2%7D%7D)
where,
= quantity of the substance remaining
= initial quantity of the substance
= time elapsed
= half life of the substance
From the information given we know:
- The initial quantity of silicone-32 is 30 g.
- The time elapsed is 300 years.
- The half life of silicone-32 is 710 years.
So, to find the quantity of silicone-32 remaining we apply the above equation
![N(t)=30\left(\frac{1}{2}\right)^{\frac{300}{710}}=30\left(\frac{1}{2}\right)^{\frac{30}{71}}\approx22.38 \:g](https://tex.z-dn.net/?f=N%28t%29%3D30%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%5Cright%29%5E%7B%5Cfrac%7B300%7D%7B710%7D%7D%3D30%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%5Cright%29%5E%7B%5Cfrac%7B30%7D%7B71%7D%7D%5Capprox22.38%20%5C%3Ag)
22.38 g of silicone-32 will be present in 300 years.
Answer:
There are loads, but for example you can find the diagonal from a lamppost the the end of its shadow if you know the height of the post and the length of the shadow.
Hope I helped x
Answer:
0.2601
Step-by-step explanation:
There are 19C16 = 969 ways for Lester to choose 16 of the 19 objects.
There are 12C11 = 12 ways to choose 11 vases, and 7C5 = 21 ways to choose a non-vase, for a total of (12)(21) = 252 ways to choose exactly 11 vases in 16 objects.
So, the probability of interest is ...
252/969 ≈ 0.2601
_____
nCk = n!/(k!(n-k)!) ... the number of ways to choose k objects from n
Answer:
2 • (2x - 3) • (3x - 2)
Step-by-step explanation:
F is the answer lol BTW it's f