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2 years ago

How do i determine a sale price?

Mathematics

1 answer:

luda_lava [24]2 years ago

3 0

Answer:

The rate is usually given as a percent.

To find the discount, multiply the rate by the original price.

To find the sale price, subtract the discount from original price.

Step-by-step explanation:

The rate is usually given as a percent.

To find the discount, multiply the rate by the original price.

To find the sale price, subtract the discount from original price.

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Anni [7]

Answer:

-12

Step-by-step explanation:

Note that when x < 6, you will use the expression -4x

f(x) = -4x

Plug in 3 for x

f(3) = -4(3)

Simplify. Multiply

f(3) = -4(3)

f(3) = -12

-12 is your answer

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2 years ago

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3 years ago

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navik [9.2K]

Answer:

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Step-by-step explanation:

<u>Step 1: Multiply</u>

<u /> $(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\$

$(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}$

$(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x} )$

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$10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Answer: Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

6 0

3 years ago

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andrey2020 [161]

Answer:

(3,0)

Step-by-step explanation:

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2 years ago

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IgorC [24]

Answer:

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Step-by-step explanation:

y = 7/5x +7

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