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Svetach [21]
3 years ago
7

HELP............Graph. y+1=1/3(x−3) (it has to have 2 points)

Mathematics
1 answer:
natta225 [31]3 years ago
5 0
The intercept method of graphing is quick and easy.

Find the x-intercept by setting y = 0 and solving for x:

y+1=1/3(x−3)   =>   0<span>+1=1/3(x−3)
  Multiply both sides by 3:  3 = x - 3.  Then x = 6, and the x-int. is (6, 0).

Find the y-int by setting x = 0 and solving for y:

</span><span>y+1=1/3(0−3)
Mult both sides by 3:  3y+3 = -3, so that 3y = -6, and y = -2.
Then the y-intercept is (0,-2).

Plot these 2 points.  Then draw a line thru them.</span>
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What is the reference angle of -3 radians? Explain.
Korolek [52]

Reference angle of -3 radians is α= - 171° 53 min 15 sec .

We know the formula for calculating circular arc

Let l=circular arc which ic according to central angle of the circle α

l=((2R π)/360)α  Let l=1 radian and R=1 (unit circle with radius R=1)

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when you count in the clockwise direction.

Good luck!!!


8 0
4 years ago
Which of the following is equivalent to 5 sqrt 13^3 ? A)13^2.
eimsori [14]
D) 13^(3/5)
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3 0
3 years ago
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If m∠BAC=(7x+1)° and m∠BCA=(5x+9)°, what is the measure of the vertex angle? Show your work to support your answer.
expeople1 [14]

Answer:

128degrees

Step-by-step explanation:

Note that the given triangle ABC is an isosceles triangle with base angles equal, hence;

m∠BAC = m∠BCA

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x = 8/2

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m∠BAC = 5x+6

m∠BAC = 5(4)+6

m∠BAC = 26 degrees

The vertex angle = 180 - (26+26)

The vertex angle = 180 - 52

The vertex angle = 128degrees

4 0
3 years ago
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