Carl is incorrect. Dave ate a higher fraction of snack bars, by 0.2 snack bars.
Carl had .5 left of a snack bar.
Dave had .3 left of a snack bar.
Tony had .5 left of a snack bar.
Gary had .0 left of a snack bar.
Tryone had .7 left of a snack bar.
If we add the above snack bars, there is a total of two remaining snack bars, meaning they only ate 12 of 14 snack bars.
Answer: E. None of the above
Step-by-step explanation:
The equation to solve the problem should look like...2x = $2.91 / 3
= 1/2kx2
U = potential energy of a spring at a certain position
k = the spring constant, specific to the spring, with units N/m.
x = distance the spring is stretched or compressed away from equilibrium
Potential Energy: Elastic Formula Questions:
1) A spring, which has a spring constant k = 7.50 N/m, has been stretched 0.40 m from its equilibrium position. What is the potential energy now stored in the spring?
Answer: The spring has been stretched x = 0.40 m from equilibrium. The potential energy can be found using the formula:
U = 1/2kx2
U = 1/2(7.50 N/m)(0.40 m)2
U = 0.60 N∙m
U = 0.60 J
Answer:
Step-by-step explanation:
8 multiplied by .75 = 6 which is 25 percent off.
Answer:
7.13 x 10^-5
Step-by-step explanation:
