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siniylev [52]
3 years ago
6

Please help me last question of the days

Mathematics
1 answer:
Flauer [41]3 years ago
3 0
Mr. Cecere scored 24 points. Mr. Neason scored 12 points. Mr. Rudolph scored 34 points.

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Anya recorded the height in inches of 10 students in her class. The results are shown below.
Juliette [100K]
D, add all your answers than divide by how many numbers there are
8 0
2 years ago
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Explain how you I got 0.16
dybincka [34]
So whats the question?
4 0
3 years ago
Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).
fomenos

Answer:

\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is 2a=|4--10|.

\implies 2a=|14|

\implies 2a=14

\implies a=7

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is (\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)

We need to use the relation a^2+b^2=c^2 to find b^2.

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

c=|6--3|=9

\implies 7^2+b^2=9^2

\implies b^2=9^2-7^2

\implies b^2=81-49

\implies b^2=32

We substitute these values into the standard equation of the hyperbola to obtain:

\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1

\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1

7 0
3 years ago
Jack and Jill were buying water jugs jack bought 2 medium sized jugs and 3 large sized jugs for 150 dollars and Jill bought 4 me
Mademuasel [1]

Answer: the cost of one medium sized jug is $60

the cost of one large sized jug is $10

Step-by-step explanation:

Let x represent the cost of one medium sized jug.

Let y represent the cost of one large sized jug.

Jack bought 2 medium sized jugs and 3 large sized jugs for 150 dollars. This means that

2x + 3y = 150 - - - - - - - - - - - 1

Jill bought 4 medium jugs and 12 large jugs for 360 dollars. This means that

4x + 12y = 360 - - - - - - - - - - - 2

Multiplying equation 1 by 4 and equation 2 by 2, it becomes

8x + 12y = 600

8x + 24y = 720

Subtracting, it becomes

- 12y = - 120

y = - 120/ - 12

y = 10

Substituting y = 10 into equation 1, it becomes

2x + 3 × 10 = 150

2x + 30 = 150

2x = 150 - 30 = 120

x = 120/2 = 60

3 0
3 years ago
Indicated operation of 2/3 + 3/8
stepladder [879]

Answer:

25/24

Step-by-step explanation:

Hope it Helps

8 0
2 years ago
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