Given:
![f(x)=\sqrt[]{5x^2-2}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B%5D%7B5x%5E2-2%7D)
f(X) will be differentiated by chain rule.
![\begin{gathered} f^{\prime}(x)=\frac{1}{2\sqrt[]{5x^2-2}}\lbrack5(2x)\rbrack \\ f^{\prime}(x)=\frac{5x}{\sqrt[]{5x^2-2}} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20f%5E%7B%5Cprime%7D%28x%29%3D%5Cfrac%7B1%7D%7B2%5Csqrt%5B%5D%7B5x%5E2-2%7D%7D%5Clbrack5%282x%29%5Crbrack%20%5C%5C%20f%5E%7B%5Cprime%7D%28x%29%3D%5Cfrac%7B5x%7D%7B%5Csqrt%5B%5D%7B5x%5E2-2%7D%7D%20%5Cend%7Bgathered%7D)
Answer:
there is no solution to the problem but after calculating and searching a possible answer is
x = -6
y = 0
Step-by-step explanation:
"Traditional IRA contributions are made with pretax dollars, while Roth IRA contributions are made with after-tax dollars" statement describes the key difference between a traditional IRA and a Roth IRA.
<u>Option: D</u>
<u>Explanation:</u>
A traditional IRA that is an individual retirement account enables investors to channel pre-tax income into assets that can increase tax postponed. Donations to a traditional IRA might be tax deductible focusing on the earnings, tax filing record and other considerations of the taxpayers.
A Roth IRA is a tax-favored retirement savings account that enables you to tax-free withdraw your savings. These are sponsored with after-tax dollars; tax-deductible investments are not. But the cash is tax-free until one begin withdrawing funds.
ANSWER:
5a+2b
add the like terms together
Answers:
x = 4
EF = 14
CF = 7
EC = 7
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Work Shown:
C is the midpoint of segment EF. This means that EC = CF. In other words, the two pieces are congruent.
Use substitution and solve for x
EC = CF
5x-13 = 3x-5
5x-13+13 = 3x-5+13
5x = 3x+8
5x-3x = 3x+8-3x
2x = 8
2x/2 = 8/2
x = 4
Now that we know that x = 4, we can use this to find EC and CF
Let's compute EC
EC = 5x - 13
EC = 5*x - 13
EC = 5*4 - 13 ... replace x with 4
EC = 20 - 13
EC = 7
Let's compute CF
CF = 3x - 5
CF = 3*x - 5
CF = 3*4 - 5 ... replace x with 4
CF = 12 - 5
CF = 7
As expected, EC = CF (both are 7 units long).
By the segment addition postulate, we can say EC+CF = EF
EC+CF = EF
EF = EC+CF
EF = 7+7
EF = 14
