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vovikov84 [41]
3 years ago
9

In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 32 vowels and 12 consonants, wha

t is the probability you will choose a consonant and then a vowel?
Mathematics
1 answer:
astraxan [27]3 years ago
8 0
0.21

Hope this helped!
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Solve for indicated variable. V= 1/3πr^2h solve for r
sergey [27]
V=\frac{1}{3}\pi r^2h\\\\\frac{1}{3}\pi r^2h=V\ \ \ \ |multiply\ both\ sides\ by\ 3\\\\\pi r^2h=3V\ \ \ \ |divide\ both\ sides\ by\ \pi h\\\\r^2=\frac{3V}{\pi h}\Rightarrow\boxed{r=\sqrt{\frac{3V}{\pi h}}}
8 0
2 years ago
You've purchased a lottery ticket and your numbers are 5-3-1. A lottery official randomly selects three balls from a set of eigh
Inessa05 [86]

Answer:

1 out of 336 chance

Step-by-step explanation:

Since you picked three numbers, you are going to put three blanks.

What to do in this situation is to have _ _ _. Since there are numbers 1-8, what you want to do is take the three biggest numbers and multiply them together. in this case, they would be 8-7-6. Multiply that and you get 336.

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2 years ago
Which best describes the triangle
sukhopar [10]

Answer:

B.

Step-by-step explanation:

6 0
2 years ago
Rewrite each sum as a product of a gcf as a new sum 9+15
Crazy boy [7]
4 +5 = 9 and 12 + 3 =15 and there is more than this
hope I helped
7 0
3 years ago
Read 2 more answers
Para reunir dinero para su gira de estudios , los alumnos de un curso deciden vender números de una rifa que se encuentran numer
QveST [7]

Respuesta:

0.53

Explicación:

Para calcular la posibilidad del evento A: "ganar la rifa comprando todos los números múltiplos de 3 o 5", debemos usar la siguiente fórmula.

P(A) = casos favorables / casos posibles

Evaluemos primero todos los casos que son múltiplos de 3, entre 1 y 100: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99. En total son 33.

Ahora, evaluemos todos los casos que son múltiplos de 3, entre 1 y 100: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100. En total son 20.

El número total de casos favorables es 33 + 20 = 53.

El número de casos posibles es el total de números de 1 a 100, es decir 100.

Luego P(A) = 53/100 = 0.53.

7 0
2 years ago
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