Question

The suspect was spotted riding the swings earlier in the day. Each swing can hold a maximum weight of 500 pounds. In order to reach the maximum weight, you would have to double the weight of the suspect and add 20 pounds less than the weight of George. Write and solve an equation to represent the suspect's weight.

Answer 1

Answer:

2y + ( x- 20)= 500

y= 520-x/2

Step-by-step explanation:

Let the weight of George be x and the weight of the suspect be y .

The swing can hold a maximum of 500 pounds .

Twice the weight of suspect added with 20 pounds less than the weight of George equals 500.

2y + ( x- 20)= 500

or

2y+x- 20 = 500

adding 20 to both sides

2y+x -20 +20= 500+ 20

or

2y +x = 520

Subtracting x from both sides

2y+ x-x = 520-x

or

2y = 520-x

Dividing by 2 on both sides

y= 520-x/2

The suspect's weight is y= 520-x/2

Answer 2

Answer:

s = 260 - g/2

Step-by-step explanation:

Given the following :

Maximum weight swing can hold = 500 pounds

Let suspect's weight = s

George's weight = g

To reach maximum weight :

Double weight of suspect + (George's weight - 20)

Hence, equation:

2s + (g - 20) = 500

2s + g - 20 = 500

2s + g = 500 + 20

2s + g = 520

2s = 520 - g

Divide through by 2

s = 260 - g/2