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Rus_ich [418]
3 years ago
14

What is 5√28 + √63 in simplest radical form? PLEASE HELP ME!

Mathematics
1 answer:
Harrizon [31]3 years ago
8 0

\bf 5\sqrt{28}+\sqrt{63}~~ \begin{cases} 28=2\cdot 2\cdot 7\\ \qquad 2^2\cdot 7\\ 63=3\cdot 3\cdot 7\\ \qquad 3^2\cdot 7 \end{cases}\implies 5\sqrt{2^2\cdot 7}+\sqrt{3^2\cdot 7} \\\\\\ 10\sqrt{7}+3\sqrt{7}\implies \stackrel{\textit{adding like-terms}}{13\sqrt{7}}

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If the measure of ZDEF is 65°, what is the measure of DE?
attashe74 [19]

Answer:

I believe it is C because i heard of that one before

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2 years ago
A plumber needs to drill a hole that is just slightly larger than 3/16 of an inch in diameter. Which measurement is the smallest
gogolik [260]

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Step-by-step explanation:  because the bottom is 16 and the others are bigger numbers

4 0
2 years ago
Gary is studying the prevalence of regional dialects. He surveyed 351 people in a region and asked what words they used for cert
chubhunter [2.5K]

Answer:

Confidence interval = ( 0.7991, 0.8647 )

Step-by-step explanation:

Sample size = n = 351

number of successes = X = 292

Sample proportion = P = \frac{X}{n}

                                     =  \frac{292}{351}

                                     = 0.831908831

confidence interval = 90%

Critical Z value  = 1.6449   [by using excel]

Confidence interval = P ± Z \sqrt{P\frac{(1-P)}{n}}

Where P = Sample proportion

           Z = critical value

           n = sample size

Confidence interval =  0.831908831 ± 1.6449 \sqrt{0.831908831\frac{(1-0.831908831)}{351}}

                                = 0.831908831 ± 1.6449 × 0.0200

                                = 0.831908831 ± 0.032898

 Lower limit             = 0.831908831 - 0.032898 = 0.7991

Upper limit               = 0.831908831 + 0.032898 = 0.8647

Confidence interval = ( 0.7991, 0.8647 )

4 0
3 years ago
Please help me!!!!!​ i need full answer.
salantis [7]

Answer:

see explanation

Step-by-step explanation:

Using the sum/ difference → product formula

cos x - cos y = - 2sin( \frac{x+y}{2})sin (\frac{x-y}{2} )

sin x - sin y = 2cos (\frac{x+y}{2} )sin (\frac{x-y}{2} )

Given

(cosA - cosB)² + (sinA - sinB )²

= [ - 2sin(\frac{A+B}{2})sin(\frac{A-B}{2} ) ]² + [ 2cos(\frac{A+B}{2} )sin(\frac{A-B}{2} ) ]²

= 4sin² (\frac{A+B}{2} )sin² (\frac{A-B}{2} ) + 4cos² (\frac{A+B}{2} )sin² ( \frac{A-B}{2} )

= 4sin² (\frac{A-B}{2} )[ sin² ( \frac{A+B}{2} ) + cos² ( \frac{A+B}{2} ) ← sin²x + cos²x = 1

= 4sin² ( \frac{A-B}{2} ) × 1

= 4sin² ( \frac{A-B}{2} ) = right side ⇒ proven

4 0
3 years ago
(1 point)
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3 years ago
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