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2 years ago

Solve the equation 2 1/3x+7=10/3x−6

Mathematics

2 answers:

Anit [1.1K]2 years ago

8 0

Answer:

-30/11

Step-by-step explanation:

21/3x-10/3x = -6-7

11/3x = -13

x = -13*3/11

x = -30/11

HOPE IT HELPS

nikitadnepr [17]2 years ago

6 0

I guess the answer is -11/3

Step-by-step explanation:

the explanation is in the picture above if you think the answer is not correct post it in comments and give me the correct question I will solve it for you

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What is angle M? Just checking work

Artist 52 [7]

Sum of interior angles = 180
180 - 60 = 120

120/4 = 30
m<L = m<A = 60
m<M = 30
m<C = m<N = 3(m<M) = 3(30) = 90

6 0

3 years ago

Is 8/4 inches greater or less than 7/2 inches

QveST [7]

I think it's less than 7/2 usually bigger numbers are less in this case.

sorry if you got that wrong but i'm 85% sure

5 0

3 years ago

Read 2 more answers

At East Middle School, there are 58 left-handed students and 609 right-handed students. The numbers of left- and right-handed st

EastWind [94]

Answer:

C. Left-handed: 48, Right-handed: 504

D. Left-handed: 30, Right-handed: 315

Step-by-step explanation:

We are given that there are 58 left-handed students and 609 right-handed students at East Middle School and these numbers of students are proportional to the number of left and right handed students at East Middle School.

Given the above information, we are are to determine which two options could be the the numbers of left-handed and right-handed students at West Junior High.

Ratio of right handed to left handed students at East Middle School = $\frac{609}{58} = 10.5$

Checking for ratios of the given options:

A. $\frac{483}{42} =11.5$

B. $\frac{378}{28} =13.5$

C. $\frac{504}{48} =10.5$

D. $\frac{560}{56} =10$

E. $\frac{315}{30} =10.5$

Therefore, the possible numbers of left-handed and right-handed students at West Junior High could be C. Left-handed: 48, Right-handed: 504 and D. Left-handed: 30, Right-handed: 315.

7 0

2 years ago

Read 2 more answers

Please help me find the total area of the composite figure below (geometry)

Akimi4 [234]

Answer:

lw + $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$ ⇒ Answer D is correct

Step-by-step explanation:

First, let us find the area of the semi-circle.

Area = $\frac{1}{2}$ × π × r²

Given that,

diameter of the semi-circle is ⇒ l

∴ radius ⇒ l / 2

Let us find it now.

Area = $\frac{1}{2}$ × π × r²

Area = $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$

Secondly, let us find the area of the rectangle.

Area = length × width

Given that,

length ⇒ l

width ⇒ w

Let us find it now.

Area = length × width

Area = l ×w

Area = lw

And now let us find the total area.

Total area = Area of the rectangle + Area of the semi - circle

Tota area = lw + $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$

8 0

2 years ago

I have to find the area of a trapezoid using the formula A= 1/2 (b1 + b2) (h)

DedPeter [7]

Answer:

190

Step-by-step explanation:

1/2(6+13)(5)

6+ 13 = 19*5 = 95

95/ 1/2= 190

7 0

3 years ago