Answer:
A whole number first term to render as fifth term a value larger than 10000, should be at least 121
Step-by-step explanation:
The formula is given as recursive since it involves the previous number of the sequence, and defined as:

we also know that the first term is 4
Then in this case, the first five terms are:

So if we want to find the first term in the case that the fifth one is greater than 10,000 using this recursive formula, now we have to start backwards, and say that the fifth term is "> 10000" and what the fourth one is.
Notice that if you have this definition for the nth term, we can obtain from it, what the previous term is to find the general rule:

So the rule is to subtract 6 from he term, and divide the subtraction by 3. Then working backwards:

therefore, the starting first term should be at least about 121 to give a fifth term larger than 10,000
Answer:
It is 9a2 − 30a + 25 The other answer is a prime number.
(
3a
−5)^2
Step-by-step explanation:
Answer:
Step-by-step explanation:
A) 3x−12≥15
3x ≥ 15 + 12
3x ≥ 27
or x≥ 9
B) 2x−5≤9
2x ≤ 9 +5
2x ≤ 14
or x ≤ 7
C) 5x+8≤53
5x ≤ 53 -8
5x ≤ 45
or x ≤ 9
D) 3x−5≥16
3x ≥ 16 + 5
3x ≥ 21
or x ≥ 7
Have a good day!
Answer:
Answer is on the pic
Step-by-step explanation:
I hope it's helpful!
Answer:
1) 5/4 or 1 1/4
2) 9/16
Step-by-step explanation:
3/4+1/2: you multiply 1/2 by 2 to get a common denominator then get 2/4, 3+2=5, 5/4 or 1 1/4
1/3+11/48: you multiply 1/3 by 16 to get common denominator & get 16/48, 16+11= 27/48, divide by 3 & get simplest form of 9/16