Question

What is an equation of the line that passes through the point (6, 6) and is parallel to

Answer 1

The equation of line that is parallel to the line 3x-2y=4 and that passes through the point (6, 6) is y=$\frac{3}{2}$x-3.

What is general equation of line?

A straight line's general equation is y = mx + c, where m denotes the gradient and y = c denotes the point at which the line crosses the y-axis. This value c is referred to as the intercept on the y-axis. y = mx + c is the equation for a straight line with a gradient of m and an intercept of c on the y-axis.

Given that: the line is parallel to the line 3x-2y=4 and that passes through the point (6, 6).

Turn 3x-2y=4 into y= (mx+c) form

Subtract 3x from both sides

-2y = 4 - 3x

Divide -2 from both sides

y= -2+(3/2)x

y= (3/2)x-2

Use slope 3/2 since the line is parallel.

Put point (6, 6) into equation to find c

6=(3/2)(6) + c

6=9 + c

c = -3

Put the value of c in the general equation y= mx+c

y= (3/2)x-3

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