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1 year ago

What is an equation of the line that passes through the point (6, 6) and is parallel to

1 answer:

4 0

The equation of line that is parallel to the line 3x-2y=4 and that passes through the point (6, 6) is y= $\frac{3}{2}$ x-3.

<h3>What is general equation of line?</h3>

A straight line's general equation is y = mx + c, where m denotes the gradient and y = c denotes the point at which the line crosses the y-axis. This value c is referred to as the intercept on the y-axis. y = mx + c is the equation for a straight line with a gradient of m and an intercept of c on the y-axis.

Given that: the line is parallel to the line 3x-2y=4 and that passes through the point (6, 6).

Turn 3x-2y=4 into y= (mx+c) form

Subtract 3x from both sides

-2y = 4 - 3x

Divide -2 from both sides

y= -2+(3/2)x

y= (3/2)x-2

Use slope 3/2 since the line is parallel.

Put point (6, 6) into equation to find c

6=(3/2)(6) + c

6=9 + c

c = -3

Put the value of c in the general equation y= mx+c

y= (3/2)x-3

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1. Contaminated water is subjected to a cleaning process. The concentration of the

Leokris [45]

Answer:

The concentration of pollutants in the water can be defined as the quotient between the mass of pollutants and the total mass of water.

Assuming that 1L of water weighs 1000 grams, we know that:

Mass of pollutants = 5mg = 0.005g.

Initial concentration = 0.005g/1000g = 0.000005

If we multiply this by 100%, we get the percentage:

0.000005*100% = 0.0005%

Now, the mass of pollutants decreases by 10% each hour.

So if initially, we have 5mg

After one hour, we will have: 5mg - 0.1*5mg = 5mg*(0.9).

After another hour, we will have: 5mg*(0.9) - 0.1*5mg*0.9 = 5mg*(0.9)^2.

And so on, then after n hours, the mass of pollutants will be:

M(n) = 5mg*(0.9)^n

Or we can write this in grams as:

M(n) = 0.005g*(0.9)^n

Then the concentration as a function of time in hours will be:

C(n) = M(n)/1000g = (0.005g/1000g)*(0.9)^n

Notice that the thing between the parentheses is the initial concentration, then if we write this in percentage form:

c(n) = 100%*(0.005g/1000g)*(0.9)^n = 0.0005%*(0.9)

The function that represents the concentration of polution in the water as a function of hours is:

c(n) = 0.0005%*(0.9)

6 0

4 years ago

An estimated regression equation that was fit to estimate ductility in steel using its carbon content was found to be significan

AnnZ [28]

Answer:

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

Step-by-step explanation:

Hello!

Considering the dependent variable:

Y: Ductility in steel.

And the independent variable:

X: Carbon content of the steel.

The linear regression was estimated and a prediction interval was calculated.

The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X= $x_{0}$ ]