What is an equation of the line that passes through the point (6, 6) and is parallel to
1 answer:
The equation of line that is parallel to the line 3x-2y=4 and that passes through the point (6, 6) is y=x-3.
A straight line's general equation is y = mx + c, where m denotes the gradient and y = c denotes the point at which the line crosses the y-axis. This value c is referred to as the intercept on the y-axis. y = mx + c is the equation for a straight line with a gradient of m and an intercept of c on the y-axis.
Given that: the line is parallel to the line 3x-2y=4 and that passes through the point (6, 6).
Turn 3x-2y=4 into y= (mx+c) form
Subtract 3x from both sides
-2y = 4 - 3x
Divide -2 from both sides
y= -2+(3/2)x
y= (3/2)x-2
Use slope 3/2 since the line is parallel.
Put point (6, 6) into equation to find c
6=(3/2)(6) + c
6=9 + c
c = -3
Put the value of c in the general equation y= mx+c
y= (3/2)x-3
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