One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel
<h3><u>Solution:</u></h3>
Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.
We have to prove that the lines are parallel.
If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.
Now, the 1st angle will be 1/6 of right angle is given as:

And now, 15 degrees is 11 times smaller than the other
Then other angle = 11 times of 15 degrees

Now, sum of angles = 15 + 165 = 180 degrees.
As we expected their sum is 180 degrees. So the lines are parallel.
Hence, the given lines are parallel
Im assuming you meant the 9th term and thats 47
Answer:
v = -8i - 6j
Step-by-step explanation:
The starting point is (9, 9)
The direction of the vector is the direction of the arrowhead.
The i is the horizontal component.
The j is the vertical component.
Therefore, to go from the start to the end of the line, we need to travel negative 8 units (horizontally) and negative 6 units (vertically).
Therefore, v = -8i - 6j
So the equation for the area of a circle is

First to find the radius, you would need to divide the diameter, 26, by half, which in this case its 13.
Replace the r variable with 13 and solve:


98 - 62 = 36
36/98 x 100 = 36.7%
answer:
Tim was 36.7% error