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gizmo_the_mogwai [7]
4 years ago
13

LOTS OF POINTS!!! PLZ HELP!!!! MATH 123

Mathematics
1 answer:
raketka [301]4 years ago
8 0

Answer: 37%

Step-by-step explanation:

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These figures are similar. The perimeter and area of one are given. The perimeter of the other is also given.
creativ13 [48]

Answer:

26.04cm^2

Step-by-step explanation:

28 divided by 20 is 1.4. 1.4 times the area will give you the area of the other figure. 1.4 x 18.6 = 26.04

5 0
4 years ago
Let C = {n ∈ Z | n = 6r – 5 for some integer r} and D = {m ∈ Z | m = 3s + 1 for some integer s}.
noname [10]

Its is true that C ⊆ D means Every element of C is present in D

According to he question,

Let C = {n ∈ Z | n = 6r – 5 for some integer r}

D = {m ∈ Z | m = 3s + 1 for some integer s}

We have to prove : C ⊆ D

Proof : Let n ∈ C

Then there exists an integer r such that:

n = 6r - 5

Since -5 = -6 + 1

=> n = 6r - 6 + 1

Using distributive property,

=> n = 3(2r - 2) +1

Since , 2 and r are the integers , their product 2r is also an integer and the difference 2r - 2 is also an integer then

Let s = 2r - 2

Then, m = 3r + 1 with r some integer and thus m ∈ D

Since , every element of C is also an element of D

Hence ,  C ⊆ D proved !

Similarly, you have to prove D ⊆ C

To know more about integers here

brainly.com/question/15276410

#SPJ4

7 0
2 years ago
Pls help immediately!!!!
alexgriva [62]
The correct answer should be A
4 0
3 years ago
Tyrone is converting StartFraction 45 Over 50 EndFraction to a percent. Which method should he use to find the percent?
ANTONII [103]

Answer:

Multiply the numerator and the denominator of the fraction by 2.

Step-by-step explanation:

Here are the options :

Divide the numerator and denominator of the fraction by 2.

Subtract 40 from the numerator and denominator of the fraction.

Multiply the numerator and the denominator of the fraction by 2.

Add 50 to the numerator and denominator of the fraction.

(45 x 2) / (50 x 2) = 90/100

Multiply 90/100 by 100 = 90%

the same answer would be gotten if 45/50 is multiplied by 100

45/50 x 100 = 90%

4 0
3 years ago
Suppose that a company claims that its air fresheners last 19 days, on average. You take many large samples, and find, each time
spayn [35]
My answer would be B 19

19 days is what they claimed but the sample is outside of the 95% confidence interval so

19 x 95% = 19.95  

Below this value, 19.95 is the probable mean number of days that the company's air fresheners last. 15,17, and 19 can be the mean number of days.
3 0
3 years ago
Read 2 more answers
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