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Alchen [17]
3 years ago
15

Which is a correct first step for solving this equation? -3x+2−5x−7=4x+2

Mathematics
2 answers:
den301095 [7]3 years ago
8 0

Answer:

(D)-8x-5=4x+2

Step-by-step explanation:

The given equation is:

-3x+2-5x-7=4x+2

Combining the like terms, we get

-3x-5x+2-7=4x+2

-8x-5=4x+2

which is the required correct step for solving the given equation.

therefore, again combining the like terms, we get

-8x-4x=2+5

-12x=7

x=\frac{-7}{12}

thus, option D is correct.

Eduardwww [97]3 years ago
4 0

D would be the correct answer in this case.

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3 years ago
Can someone help please 3x-y=13 A. (6,5) B.(3,-4) C. (6,5) and (3,-4) D. neither
gavmur [86]

Answer:

C. (6, 5) and (3, -4)

Step-by-step explanation:

Given the equation 3x - y = 13, we need to figure out which points satisfy it. In order for an ordered pair to satisfy an equation, when we plug the x-coordinate in for x and the y-coordinate in for y, the equation should hold true.

Let's try with (6, 5):

3x - y = 13

3 * 6 - 5 =? 13

18 - 5 =? 13

13 = 13

Since this is true, we know that (6, 5) is indeed a solution.

Now let's try with (3, -4):

3x - y = 13

3 * (3) - (-4) =? 13

9 + 4 =?13

13 = 13

Again, since this is true, then (3, -4) must be a solution.

Thus, the answer is C.

<em>~ an aesthetics lover</em>

6 0
3 years ago
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konstantin123 [22]

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Step-by-step explanation:

7 0
3 years ago
The area of a rectangle is the rectangle’s length times its width. Write a program that asks for the length and width of two rec
Mnenie [13.5K]

Answer:

Using c++

Check the image for colors.

Step-by-step explanation:

#include <iostream>

using namespace std;

int main()

{

   float length1,length2,width1,width2,area1,area2;

   

   cout<<"length of Rectangle 1\n";

   cin>>length1;

   cout<<"\nwidth of Rectangle 1\n";

   cin>>width1;

   cout<<"\nlenght of Rectangle 2\n";

   cin>>length2;

   cout<<"\nwidth of Rectangle 2\n";

   cin>>width2;

   

   area1=length1*width1;

   area2=length2*width2;

   

   if (area1<area2)

   {cout << "\nRectangle 2 has greater area";}

   else {

               if (area1>area2)

                  {cout << "\nRectangle 1 has greater area";}

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}

7 0
3 years ago
Part A - Construct a circle of any radius, and draw a chord on it. The construct the radius of the circle that bisects the chord
Julli [10]

Answer:

It can be concluded that the intersection of a chord and the radius that bisects it is at right angle. The two are perpendicular.

Step-by-step explanation:

i. Construct the required circle of any radius as given in the question, then locate the chord. A chord joins two points on the circumference of a circle, but not passing through its center.

ii. Construct the radius to bisect the chord, dividing it into two equal parts.

Then it would be observed that the intersection of a chord and the radius that bisects it is at right angle. Thus, the chord and radius are are perpendicular to each other.

The construction to the question is herewith attached to this answer for more clarifications.

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