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Sever21 [200]
3 years ago
7

Suppose that a company claims that its air fresheners last 19 days, on average. You take many large samples, and find, each time

, that the mean number of days of the sample is outside the 95% confidence interval. Based on this information alone, which of the following is probably not the mean number of days that the company's air fresheners last? A. 17 B. 19 C. 15 D. 13
Mathematics
2 answers:
Andreas93 [3]3 years ago
8 0

Answer: B 19

Step-by-step explanation:

spayn [35]3 years ago
3 0
My answer would be B 19

19 days is what they claimed but the sample is outside of the 95% confidence interval so

19 x 95% = 19.95  

Below this value, 19.95 is the probable mean number of days that the company's air fresheners last. 15,17, and 19 can be the mean number of days.
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