Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:
![\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac2n%5Cright%5D%2C%5Cleft%5B%5Cdfrac2n%2C%5Cdfrac4n%5Cright%5D%2C%5Cleft%5B%5Cdfrac4n%2C%5Cdfrac6n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7B2%28n-1%29%7Dn%2C2%5Cright%5D)
Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,
where 
. Each interval has length 
.
At these sampling points, the function takes on values of
We approximate the integral with the Riemann sum:
Recall that
so that the sum reduces to
Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:
Just to check:
Answer:
1. A=300miles B=300
2.A=50mph B=40mph
3.A=300miles B=200miles
Step-by-step explanation:
<em><u>1.</u></em>
Simply just read the graph
<em><u>2.</u></em>
do not let line B fool you, car b may look like it was faster, but unlike car a it started at 100 miles rather than 0 miles
<em><u>3.</u></em>
Just like 2, do not be fooled, you have to subtract to find b but a is easily found
I hope this helps u pls give a brainliest and a thx ;)
Step-by-step explanation:
I think we cannot find the sum because it will continue on so the series is multiply by 4
Answer:
1/3(n) - 3 < 6; n < 27
Step-by-step explanation:
" 3 subtracted from one third of a number"
= 1/3(n) - 3
given that this is less than 6:
1/3(n) - 3 < 6
1/3(n) < 6 +3
1/3(n) < 9
n < 27
Answer:True, true, true.
Step-by-step explanation:
