Question

The sum of two consecutive integers is sixty-five. Find the smaller of the two numbers.

Answer 1

Answer:

32

Step-by-step explanation:

We can write an algebraic equation to solve this situation: $x + x + 1 = 65$, where x = first integer (small number) and x + 1 = the following integer.

Step 1: Combine like terms.

• $(x+x)+1=65$
• $2x + 1 = 65$

Step 2: Subtract 1 from both sides.

• $2x + 1 - 1 = 65 - 1$
• $2x = 64$

Step 3: Divide both sides by 2.

• $2x/2 = 64/2$
• $x = 32$

Therefore, the smaller number is 32 while the larger number is 33.

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