6wholes and 1/4 ÷ 5wholes
1 answer:
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The tangent to at the point (0, 5) has a slope equal to the derivative evaluated at
.
This tangent passes through the point (0, 5), so its equation is
The normal line passes through the same point, but is perpendicular to the tangent line, so its slope is the negative reciprocal of the slope of the tangent. So the equation for the normal line is
Answer:
a
Step-by-step explanation:
A perpendicular bisector, intersects a line at its mid point and is perpendicular to it.
Calculate slope m using the slope formula
m =
with (x₁, y₁ ) = (- 7, 1) and (x₂, y₂ ) = (9, 13)
m = =
=
=
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= -
← slope of perpendicular bisector
Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
(,
)
using (x₁, y₁ ) = (- 7, 1) and (x₂, y₂ ) = (9, 13) , then
midpoint = ( ,
) = (
,
) = (1, 7 )
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - , then
y = - x + c ← is the partial equation
To find c substitute the midpoint (1, 7) into the partial equation
7 = - + c ⇒ c =
+
=
y = - x +
← equation of perpendicular bisector