An extraneous solution is a root of a transformed equation which is not a root of the original equation because it was not included in the domain of the original equation.
Ahmed is solving for x.
His steps were:
Since cube roots <u>do not give two solutions when solved</u>, it is <u>not necessary </u>to check his answers for extraneous solutions.
The answer is 256pi if you have a calculator, and it says to put it in 3.14 for pi, do the same steps I show here, but instead of pi, you would put 3.14. But I hope this helps you