True, the nonlinear optimization problem is an optimization problem in which at least one term in the objective function or a constraint is nonlinear.
Given that,
A statement of nonlinear optimization is given,
We have to determine whether the statement is true or false.
<h3>What is arithmetic?</h3>
In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,
Here,
The nonlinear optimization problem is an optimization problem in which at least one term in the objective function or a constraint is nonlinear, is true, Because its basic definition of nonlinear optimization.
Thus, the given statement is true.
Learn more about arithmetic here:
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The correct is:
![[(-9,3),\:(-5,1),\:(7,-5),\:(4,3)]](https://tex.z-dn.net/?f=%5B%28-9%2C3%29%2C%5C%3A%28-5%2C1%29%2C%5C%3A%287%2C-5%29%2C%5C%3A%284%2C3%29%5D)
The definition of a function is that for every value of 
we get one from 
.
In the first appears 
y 
, it is not a function, since it does not meet the definition given above, there can only be one value for x, if there are 
or more, called relation.
In 2 repeat: 
and 
In 3 repeat: 
and 
Divide both of them by 8
the answer would be: 7/10
hope that helps :)
Answer:
1190 m^3
Step-by-step explanation:
l = 1700 cm = 17 m
b = 14 m
h = 1000 cm = 10 m
Total volume = l × b × h
= 17 × 14× 10
= 2380 m^3
since it is half filled ,
Volume is half , so,
volume of water in pond = 2380 ÷ 2
= 1190 m^3
Answer: You apply the trigonometric ratios of Sine, Cosine and Tangent.
Step-by-step explanation: In a question such as this one of the angles must be given, which is labeled the reference angle. We already know one angle is 90 degrees in a right angled triangle, so the other two angles whatever their size is, must both add up to 90, which means they are both acute angles. If one side is given, for instance 10 units, and one of the two acute angles is given, for example 30 degrees, then the line facing the reference angle (30 degrees) would be the OPPOSITE. The line that lies between the angles 30 and 90 would be the ADJACENT while the third side which is the longest would be the HYPOTENUSE.
So if for instance, the opposite line is 10 units, and you are required to calculate the other line, the adjacent, AS LONG AS YOU HAVE BEEN GIVEN A REFERENCE ANGLE, you can simply calculate as follows;
TanX = opposite/adjacent (and that becomes)
Tan 30 = 10/adj
Adj = 10/Tan 30
Adj = 10/0.5774
Adj = 17.32
**Note that the use of angle 30 was just for the sake of explanation. Your reference angle whatever it is, would be provided by your examiner**
