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mars1129 [50]
3 years ago
10

Please help me. please please please​

Mathematics
1 answer:
Anastasy [175]3 years ago
8 0

Answer:

\frac{27}{8}

Step-by-step explanation:

\left(\frac{16}{81}\right)^{\frac{-3}{4}}=\frac{16^{\frac{-3}{4}}}{81^{\frac{-3}{4}}}

=\frac{2^{-3} }{3^{-3} }

=\frac{\frac{1}{8}}{\frac{1}{27}}

=\frac{1*27}{8*1}

=\frac{27}{8}

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Please help if you want brianleist!! :) uhm don't mind update- NO LINkS child..
Kipish [7]

Answer:

5\frac{7}{8} is the answer.

Step-by-step explanation:

I added all the fractions up.

4 0
3 years ago
What's (4x + 8) + (7x + 3)
vodka [1.7K]
11x + 11 is you answer.
6 0
3 years ago
Read 2 more answers
Please answer this (photo below)
lozanna [386]

Answer:

Please see attached image for the graph

Step-by-step explanation:

To graph the elevation versus time, we start by plotting the first point at time zero (when the climb begins) when Zane is 20 meters below the edge (-20 meters). This corresponds to the point (0, -20).

One second later (1 in the horizontal axis), Zane has moved up 4 meters, now reaching -16 meters. This is the point (1, -16) on the graph.

One second later at time 2 seconds, he is another 4 meters up which corresponds to the point (2, -12) on the graph.

you can go on like this plotting more points on the graph.

Please see the attached image that illustrates this and shows the appropriate line that represents Zane's position versus time (pictured in red)

7 0
4 years ago
Carlos has four notes in his wallet: $5, $10, $20 and $50. He takes out two notes at random.
Alex787 [66]
5 and 10
5 and 20
5 and 50
10 and 20
10 and 50
20 and 50
1/4 for 5$
1/4 for 50$

3 0
3 years ago
Simplify this expression with only positive exponents. ​
Black_prince [1.1K]

Answer:

\frac{2x}{y^{-1}}=2xy

Step-by-step explanation:

To simplify the expression \frac{2x}{y^{-1}} you must:

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-1}=\frac{1}{a}\\\\y^{-1}=\frac{1}{y}\\\\\frac{2x}{y^{-1}}=\frac{2x}{\frac{1}{y}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{\frac{b}{c}}=\frac{a\cdot \:c}{b}\\\\\frac{2x}{\frac{1}{y}}=\frac{2xy}{1}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{1}=a\\\\\frac{2xy}{1} = 2xy

Therefore,

\frac{2x}{y^{-1}}=2xy

7 0
3 years ago
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