Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:ed44
Step-by-step explanation:
Adds 4 each time and 5-4=1 so nth term is 4n + 1
Step 1: Keep the denominator the same. Step 2: Add or subtract the numerators. Step 3: If the answer is an improper form, reduce the fraction into a mixed number. ... Step 1: Find the Lowest Common Multiple (LCM) between the denominators.
7/4 5/6
7+5=
7/5
1 2/5
Answer:
Greater than
Step-by-step explanation:
(<em>C</em> × 9/5) + 32 = <em>F</em>
(23°C × 9/5) + 32 = 73.4°F
Therefore, 23°C is greater than room temperature (70°F).