The numbers are "x" and "y"
Therefore, we can suggest this system of equations:
x+y=10 ⇒x=10-y
xy=-60
Solve this system of equations by substitution method.
(10-y)y=-60
10y-y²=-60
y²-10y-60=0
Solve this square equation:
y=[10⁺₋√(100+240)]/2=(10⁺₋2√85)/2=5⁺₋√85
We have two solutions:
y₁=5-√85 ⇒x₁=10-(5-√85)=5+√85
y₂=5+√85 ⇒x₂=10-(5+√85)=5-√85
Answer: the numbers are (5-√85) and (5+√85)
Answer:
c
Step-by-step explanation:
hope this hellpppeedd
Answer:
VF= $3.281,42
Interes= 3.281,42 - 3.000= $281.42
Step-by-step explanation:
Dada la siguiente información:
Prestamo (P)= $3.000
Tasa (i)= 0,015/2= 0,0075
Cantidad de periodos (n)= 6*2= 12 semestres
<u>Para calcular el valor final del prestamos, tenemos que usar la siguiente formula:</u>
VF= P*(1 + i)^n
VF= 3.000*1,0075^12
VF= $3.281,42
Interes= 3.281,42 - 3.000= $281.42
Answer:
a) x > − 24
b) x < − 3
c) q < 56
Step-by-step explanation:
a) −2/5x−9<9/10
<=> 2/5x + 9 > − 9/10
<=> 2/5x > − 9/10 − 9
<=> 2×2/2×5x > − 9/10 − 9×10/10
<=> 4/10x > − 99/10
<=> x > − 99/4
<=> x > − 24
b) 4x+6<−6
<=> 4x < − 6 − 6
<=> 4x < − 12
<=> x < − 12/4
<=> x < − 3
c) q+12−2(q−22)>0
<=> q+12−2q −2×(−22)>0
<=> (q−2q) + (12+ 44) >0
<=> −q + 56 >0
<=> q < 56
Relations are functions if every input has exactly one output
So, the first on is a function because each x value has one y value. Meaning, for example, (3,2), 3 is the x value, which is the input, and 2 is the y value which is the output. But within that set of relations, 3 only has one output which is 2.
The second one is not a function because 2 has 2 outputs. (2,3) and (2,5). 2 has an output of 3 and 5. Every input can only have one output. So this isn't a function
The third one isn't a function because 6 has two outputs. (6,3) and (6,6). 6 has two outputs of 3 and 6, so it's not a function
The last one isn't a function either because 6 has two outputs. (6,8) and (6,4). 6 has the outputs of 8 and 4. So, it is not a function
Hope that helps :)