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mr_godi [17]
4 years ago
14

What is the value of c? Please help me. :(

Mathematics
1 answer:
AlexFokin [52]4 years ago
4 0

Answer:

       

Step-by-step explanation:

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23f written as a verbal expression
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Twenty three times a number.
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3 years ago
Use a trigonometric identity to find the indicated value in the specified quadrant.
aleksandr82 [10.1K]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2782751

_______________


Cosine and secant functions are reciprocal, which means

\mathsf{sec\,\theta=\dfrac{1}{cos\,\theta}}


So, if  \mathsf{cos\,\theta=\dfrac{3}{8},}  then

\mathsf{sec\,\theta=\dfrac{1}{~\frac{3}{8}~}}\\\\\\
\mathsf{sec\,\theta=\dfrac{8}{3}\qquad\quad\checkmark}


I hope this helps. =)


Tags:   <em>cosine secant cos sec relation reciprocal trig trigonometry</em>

7 0
3 years ago
Describe in words the region of R3 reperesented by the equations or inequalities x2+y2+z2≤3
Vaselesa [24]

Answer:

The region represented by the equation is a full sphere of radius √3 centered in the origin of coordinates.

Step-by-step explanation:

<em>In a plane xy, the equation that represents a circle with center in the origin, of radius r is</em>

x^2+y^2=r^2

<em>in R³, or a space xyz, we can represent a sphere with its center in the origin, and of radius r, with the equation</em>

x^2+y^2+z^2=r^2

So, in this problem we have that

3=r^2

which means that the sphere has a radius of √3.

<u>Finally, our equation is an inequality</u>, and the sphere is equal to, and less than, the calculated radius.

Therefore, the sphere is "full" from the surface to its center.

8 0
3 years ago
It’s <br><br> Less <br><br> More <br><br> The same amount of
Jet001 [13]
More energybif u have breakfast
5 0
3 years ago
The theme park company is building a scale model of the killer whale stadium main show tank for an investor's presentation. Each
Angelina_Jolie [31]

Since

the mock up is 6 times smaller than the actual killer whale stadium, then the

radius of the mock up would be:

radius

mock up = 70 / 6 = 11.67

Therefore

the volume of the mock up would be one fourth of the volume of a sphere since the

shape is like one fourth of a sphere.

V mock

up = ¼ * Volume of sphere

V mock

up = ¼ * 4/3 * pi * r^3

V mock

up = 0.25 * 4/3 * pi * 11.67^3

V mock

up = 1664.34

 

Therefore

the ratio is

Actual

volume / V mock up = 359007 / 1664.34 = 215.7

 

Therefore the mock up is about 216 times smaller than the

actual stadium.

╦────────────────────────────╦

│Hope this helped  _____________________│    

│~Derelis ____________________________ │

╨___________________________________╨                  

5 0
3 years ago
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