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2 years ago

Find the selling price of a $20 item after a 20% markup.

Mathematics

1 answer:

nevsk [136]2 years ago

4 0

Answer:

$24

Step-by-step explanation:

For a markup, use the formula a = ( 1 + p ) × w.

!!! Remember, a is the selling price, and w is the original price !!!

!!! The p is the percent in decimal form. 20% as a decimal is 0.20 (move the decimal twice to the left) !!!

Inserting the values, it should look like a = ( 1 + 0.20 ) × 20

a = 1.20 × 20

a = 24

Hence, the new selling price is $24.

Hope this helps! :)

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Calculate the size of Angle A when two known angles are 80 degrees and 30 degrees

yan [13]

Answer:

70°

Step-by-step explanation:

every triangle has a total of 180°, therefore 180-80-30=70°

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6 0

2 years ago

Pls I need help with this

LiRa [457]

Answer:

third side = 4

Step-by-step explanation:

third side is hypoenuse as it is opposite to 90 degree.

using pythagoras theorem

(perpendicular)^2 + (base)^2 = (hypotenuse)^2

2^2 + (2 $\sqrt{3$ )^2 = hypotenuse^2

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$\sqrt{16}$ = hypotenuse

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2 years ago

Which of the following is a solution of x2 + 6x = −18? x = 3 − 3i x = −3 + 3i x = −6 + 3i x = 6 − 3i

Marina86 [1]

Step 1 ) Move all terms right side of the equation.

$\displaystyle\ x^{2} + 6x = -18$

$\displaystyle\ x^{2} + 6x + 18 = -18 + 18$

$\displaystyle\ x^{2} +6x + 18 = 0$

Step 2 ) Apply quadratic formula. (Note: There are 2 solutions)

$\displaystyle\ x^{2} +6x + 18 = 0$

$\displaystyle\ x = \frac{-b\sqrt{b^{2}-4ac}}{2a}, \displaystyle\ x = \frac{-b-\sqrt{b^{2}-4ac}}{2a}$

$\displaystyle\ x = \frac{-6+\sqrt{6^{2}-4 * 18}}{2} , \displaystyle\ x = \frac{-6-\sqrt{6^{2}-4*18}}{2}$

$\displaystyle\ x = \frac{-6+6i}{2}$ ,

$\displaystyle\ x = \frac{-6-6i}{2}$

Step 3 ) Simplify.

$\displaystyle\ x = \frac{-6+6i}{2}$ ,

$\displaystyle\ x = \frac{-6-6i}{2}$

$\displaystyle\ x = -3+ 3i$ ,

$\displaystyle\ x = -3 - 3i$

Since the options only provide one of the answer we found, the answer is...

$\displaystyle\ x = -3 - 3i$

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