Let x be the first digit.
Let y be the second digit.
Let z be the third digit.
x+y+z=18
y= (-2)(-4)
y= 8
x= 3^2
x= 9
Therefore z=1.
The number is
= 100x+10y+z
= 100(9)+10(8)+(1)
= 981
<span>standard deviation and variance</span>
Answer:
33
Step-by-step explanation:
ik its ritgh
Then I'll definitely will ask you questions about maths :)
Answer:
3(4a−5b+2)
Step-by-step explanation:
The answer should have originally been 3(4a-5b+2)
3(4a+5b+3)= 12a+15b+9 which is incorrect.
