Answer for a(x+b)=c;2(x+1)=9

Mathematics

1 answer:

babunello [35]2 years ago

6 0

Ax+ab=c; 2x2 = 9

Try to take it from there

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Answer:

False, counterexample below

Step-by-step explanation:

Denote the unit vectors of R^3 by $e_1=(1,0,0), e_2=(0,1,0), e_3=(0,0,1)$ . Now consider $v_1=e_1, v_2=2e_1$ and $v_3=e_3$ . We have that $v_1, v_2,v_3 \in \mathbb{R}^3$ . Also, the vector $v_3$ is not a linear combination of $v_1, v_2$ because any linear combination of these two vectors will have third coordinate zero, but v_3 has third coordinate 1 so they can't be equal.

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Question 4 of 25

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Answer:

Step-by-step explanation:

We are looking for P(58 < x < 64). We need to find the percentage to the left of the z-scores for each of these numbers. To find the z scores, use the formula:

$z=\frac{x_i-\bar{x}}{\sigma}$

$z=\frac{58-62}{4}$ which gives us a z-score of -1. The percentage of numbers to the left of a z-score of -1 is .1586553

Now for the other z-score:

$z=\frac{64-64}{4}$ which gives us a z-score of .5. The percentage of numbers to the left of a z-score of .5 is .69146246

The lower percentage subtracted from the higher gives the area in question:

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Answer:

<h2>Answer is in the attachment! </h2>

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