Answer for a(x+b)=c;2(x+1)=9

Mathematics

1 answer:

babunello [35]3 years ago

6 0

Ax+ab=c; 2x2 = 9

Try to take it from there

You might be interested in

What is the greatest common factor of 15 and 64

Neko [114]

35.
Hope my answer helps.

3 0

3 years ago

Help. help. help.<br>no link pls.

kondaur [170]

Answer:

x + 2, x ≠ -2

Step-by-step explanation:

Note that F(x) = x^2 + 4x + 4 factors into (x + 2)^2, and that we are dividing this by g(x) = x + 2. The quotient is x + 2, which in this problem has been named h(x).

The quotient (f/g)(x) is therefore x + 2 EXCEPT that this is not defined at x = -2, because the denominator, x + 2, will be zero there, undefined.

8 0

3 years ago

Exit Ticket Anyone Can help me?

Umnica [9.8K]

Answer:

okay, so 1 1/6 can be converted to 7/6.

2 3/8 can be converted to 19/8

now find a common denominator, which is 24

7/6 would turn into 28/24

19/8 would turn into 57/24

now add! 28+57= 85/24

85/24

Step-by-step explanation:

please consider marking me as brainliest, my answer took alot of time and I am trying to rank up! have a great day lovely!!

4 0

3 years ago

A recent survey showed that in a sample of 100 elementary school teachers, 15 were single. In a sample of 180 high school teache

trapecia [35]

Answer:

By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single

Step-by-step explanation:

let p1 be the proportion of elementary teachers who were single

let p2 be the proportion of high school teachers who were single

Then, the null and alternative hypotheses are:

$H_{0}$ : p2=p1

$H_{a}$ : p2>p1

We need to calculate the test statistic of the sample proportion for elementary teachers who were single.

It can be calculated as follows:

$\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of high school teachers who were single ( $\frac{36}{180} =0.2$ )
p is the proportion of elementary teachers who were single ( $\frac{15}{100} =0.15$ )