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Mars2501 [29]
3 years ago
7

At the frozen yogurt shop, a machine fills cups with 4 ounces of frozen yogurt before adding the toppings. After the cups are fi

lled, customers add as many toppings as they want without exceeding a total weight of 6 ounces. Which of the following represent the acceptable weights for the frozen yogurt options? Select all that apply:
A.) 0 < x ≤ 6
B.) 0 < x ≤ 3
C.) 4 ≤ x ≤ 6
D.) x ≤ 6
E.) |x - 5| ≤ 1
F.) |x - 2| ≤ 6
Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0
The yogurt can weigh anything above or equal to 4 ounces and less or equal to 6 ounces.
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earnstyle [38]
C. 4x

Have a good day ;)

7 0
3 years ago
Lisa is mailing a letter to a friend. Postage costs $0.32 for the first ounce and $0.23 for the additional ounce. How heavy can
Advocard [28]

Answer: 8.3 ounces

Step-by-step explanation:

simple, there's a flat fee for 1 ounce, then 23 cents for each ounce following.

so $2 - $0.32 = $1.68

1.67 / 0.23 = 7.3 ounces

7.3 ounces + 1 ounces (from the flat fee we subtracted)

which equals 8.3

7 0
3 years ago
PLEASE HELP (50 points)
rjkz [21]

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6 0
3 years ago
When using blocking to deal with extraneous factors in an experiment, the
Elena L [17]

Answer:

<em>False</em>

Step-by-step explanation:

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6 0
3 years ago
What are the ordered pairs of the
9966 [12]

Start by writing the system down, I will use y to represent f(x)

y=x^2-5x+3\wedge y=-3

Substitute the fact that y=-3 into the first equation to get,

-3=x^2-5x+3

Simplify into a quadratic form (ax^2+bx+c=0),

x^2-5x+6=0

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

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which then must factor into

(x+m)(x+n)=0

And the solutions will be m,n.

Clearly for small coefficients like ours 5,6, this is very easy to figure out. To get 5 and 6 we simply say that m=3, n=2.

This fits the definition as 5=3+2 and 6=2\cdot3.

So as mentioned, solutions will equal to m=3, n=2 but these are just x-values in the solution pairs of a form (x,y).

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are (2,0) and (3,0).

Hope this helps :)

5 0
3 years ago
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