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Sav [38]
3 years ago
14

-6z = 72 I’m just bad at math ;-;

Mathematics
1 answer:
nignag [31]3 years ago
4 0

Answer: z = -12

Step-by-step explanation:

-6z = 72

divide both sides by -6

z = -12

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Solve the system of equations for x and y.<br> y = x + 5<br> y = 2x + 2
DIA [1.3K]
Answer (x,y) (3, -2)

Explanation:
using the
substitution method
y
=
x
−
5
→
(
1
)
y
=
−
2
x
+
4
→
(
2
)
since both equations are expressed in terms of x we

can equate them
⇒
x
−
5
=
−
2
x
+
4
add 2x to both sides
2
x
+
x
−
5
=
−
2
x
+
2
x
+
4
⇒
3
x
−
5
=
4
add 5 from both sides
3
x
+
5
−
5
=
4
+
5
⇒
3
x
=
9
divide both sides by 3
3
x
3
=
9
3
⇒
x
=
3
substitute this value in
(
1
)
y
=
3
−
5
=
−
2
As a check
substitute these values into
(
2
)
right
=
−
6
+
4
=
−
2
=
left
⇒
point of intersection
=
(
3
,
−
2
)
3 0
3 years ago
To find the quotient of 726.02 and 1,000, move the decimal point in 762.02___Places to the ____
Alja [10]

from blank one five

from blank two is right

8 0
3 years ago
Abe,a plumber, charges $50 per hour for making an in-home visit. The Plumbing Service $65 per hour but no set free for a visit.
ArbitrLikvidat [17]

Answer:

Plumber: 13 hours

Plumbing service: 10

Step-by-step explanation:

What you have to find is LCM(least common multiple in order to find the lcm all you have to do is list all the multiples and find their common multiple.

5 0
3 years ago
Read 2 more answers
Solve 5x^2 - 7x+2 -0 by completing the square. What are the solutions?
trapecia [35]

5<em>x</em>² - 7<em>x</em> + 2 = 0

5(<em>x</em>² - 7/5 <em>x</em>) + 2 = 0

5(<em>x</em>² - 7/5 <em>x</em> + 49/100 - 49/100) + 2 = 0

5(<em>x</em>² - 2 • 7/10 <em>x</em> + (7/10)²) - 49/20 + 2 = 0

5(<em>x</em> - 7/10)² - 9/20 = 0

5(<em>x</em> - 7/10)² = 9/20

(<em>x</em> - 7/10)² = 9/100

<em>x</em> - 7/10 = ± √(9/100)

<em>x</em> - 7/10 = ± 3/10

<em>x</em> = 7/10 ± 3/10

<em>x</em> = 10/10 = 1   or   <em>x</em> = 4/10 = 2/5

6 0
3 years ago
The expedition team plan a final practice run to test the range of their communication equipment. One member travels a distance
podryga [215]

Answer:

We need to sketch the problem first.

Find the size of angle R.

One member travels a distance of 12km due north. Another team member heads 50degree east of north and travels a distance of 10km.

If se substute 50° of 180 we have

180-50=130°

The distance between the two team members is the missing side.

We know two sides and included angle, so we use the cosine rule.

A2+b2+c2-2bcCosA

= 102+122-(2x10x12xcos130°)

=100+144-(-147.08)

=100+144+147.08

=391.08

A==SQRT391.08

=19.775

19.7km

Step-by-step explanation:

Download docx
4 0
3 years ago
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