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3 years ago

What is the domain of the following list of ordered pairs? (-1,2),(3,4),(0,-3),(1,-6)

Mathematics

2 answers:

Molodets [167]3 years ago

5 0

-1,0,1,3 because domain is the x values

Ugo [173]3 years ago

5 0

Domain is the x-values so take out all the x values from the given ordered pairs:

(-1, 2) -> -1
(3, 4) -> 3
(0, -3) -> 0
(1, -6) -> 1

The domain is {-1, 0, 1, 3}

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Answer:

a) $P(X=2)=\frac{2}{15}$

b) $P(X=3)=\frac{1}{30}$

c) P(X=6)=0

d) P(X=9)=0

Step-by-step explanation:

We know that are 4 men and 6 women are ranked according to their scores on an exam. X = 1 indicates that a man achieved the highest score on the exam.

a) We calculate P(X=2).

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$C^{10}_{2}=\frac{10!}{2! (10-2)!}=\frac{10\cdot 9\cdot 8!}{2\cdot 1 \cdot 8!}=45$

We calculate the number of favorable combinations

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We get that is

$\boxed{P(X=2)=\frac{6}{45}=\frac{2}{15}}$

b) We calculate P(X=3).

We calculate the number of possible combinations

$C^{10}_{3}=\frac{10!}{3! (10-3)!}=\frac{10\cdot 9\cdot 8\cdot 7!}{3\cdot2\cdot 1 \cdot 7!}=120$

We calculate the number of favorable combinations

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We get that is

$\boxed{P(X=3)=\frac{4}{120}=\frac{1}{30}}$

c) We calculate P(X=6). This case is not possible because 6 men cannot be selected because we have been given 4 men.

We conclude P(X=6)=0.

d) We calculate P(X=9). This case is not possible because 9 men cannot be selected because we have been given 4 men.

We conclude P(X=9)=0.

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