All categories

3 years ago

45 POINTS! PLEASE HELPPPPPPPPPPPPPP!

Mathematics

1 answer:

VMariaS [17]3 years ago

7 0

Answer:

This is a direct variation where the constant of variation is 5/9

Step-by-step explanation:

The equation for direct variation is y = kx

5x-9y =0

Lets try to get this equation in the above form

Add 9y to each side

5x-9y +9y = 9y

5x = 9y

Divide each side by 9

5/9 x = 9y/9

5/9x = y

This is in the form y = k x where k =5/9

You might be interested in

Can someone help me on letters B and C?

skelet666 [1.2K]

Step-by-step explanation:

if he is just talking about the length than it is,

4(13x + 8)

of he is talking about overall length he swam than,

4(13x + 8) + 3(7x - 2)

if x = 12

than

perimeter = 2l + 2b

so, after inserting the values we got,

→ 2[13(12) + 8] + 2[7(12) - 2]

→ 2 (156 + 8) + 2(84 - 2)

→ 2 × 164 + 2 × 82

→ 328 + 164

→ 492 ft. ← perimeter

and yeah, according to me

a is wrong as,

formula of perimeter = 2l + 2b or 2(l+b)

so, the answer should be,

2(13x + 8) + 2(7x - 2) or 2 [ (13x + 8) + (7x - 2)

hope this answer helps you dear...take care and may u have a great day ahead!

4 0

2 years ago

A scientist has discovered an organism that replicates at a rate of five per hour and lives for one week. Each replicated organi

bezimeni [28]

A)2,801

write an equation for the translation of y= [x]. 16.5 units

4 0

4 years ago

An object is launched from ground level with an initial velocity of 120 meters per second. For how long is the object at or abov

babunello [35]

Answer:

D) 14 seconds

Step-by-step explanation:

First we will plug 500 in for y:

500 = -4.9t² + 120t

We want to set this equal to 0 in order to solve it; to do this, subtract 500 from each side:

500-500 = -4.9t² + 120t - 500

0 = -4.9t²+120t-500

Our values for a, b and c are:

a = -4.9; b = 120; c = -500

We will use the quadratic formula to solve this. This will give us the two times that the object is at exactly 500 meters. The difference between these two times will tell us when the object is at or above 500 meters.

The quadratic formula is:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Using our values for a, b and c,

$x=\frac{-120\pm \sqrt{120^2-4(-4.9)(-500)}}{2(-4.9)}\\\\=\frac{-120\pm \sqrt{14400-9800}}{-9.8}\\\\=\frac{-120\pm \sqrt{4600}}{-9.8}\\\\=\frac{-120\pm 67.8233}{-9.8}\\\\=\frac{-120+67.8233}{-9.8}\text{ or }\frac{-120-67.8233}{-9.8}\\\\=\frac{-57.1767}{-9.8}\text{ or }\frac{-187.8233}{-9.8}\\\\=5.3242\text{ or }19.1656$

The two times the object is at exactly 500 meters above the ground are at 5 seconds and 19 seconds. This means the amount of time it is at or above 500 meters is

19-5 = 14 seconds.

6 0

3 years ago

Every even number,except 2,is composite

Degger [83]

Yes. That's correct. Is that what you're asking...? To clarify, prime numbers have a single factor (one and itself) , composite numbers have multiple factors.

5 0

4 years ago

Find the zeros of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients

Anna [14]

Answer:

Zeros would be x= 0, -2

Step-by-step explanation:

hope this helps :)

6 0

3 years ago