We know that the points at which the parabola intersects the x axis are
(-5,0) and (1,0)
So the extent between these two points would be the base of the triangle
lets find the length of the base using the distance formula
![\sqrt{[(-5-1)^{2}+(0-0)^{2} ]}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%5B%28-5-1%29%5E%7B2%7D%2B%280-0%29%5E%7B2%7D%20%5D%7D%20%20)
the base b=6
We will get the height of the triangle when we put x=0 in the equation
y=a(0+5)(0-1)
y=-5a
so height = -5a (we take +5a since it is the height)
We know that the area of the triangle =
× 6 × (5a) = 12
15a=12
a= 
Answer:
it is 10 times greater
Step-by-step explanation:
hope this helps :)
Perimeter = 2base + 2base
82 - 2(32) = 18 : 2 = 9
area = 9*32 = 288mm^2
A_n= a₁+(n-1)d
a₁ first term
n terms
d distance between each value
a_n= 12+(405-1)(5)=2032
Answer: primeter is 20
Area :
Step-by-step explanation:
Height : 4
Base : 6
Prim - 6+6+4+4=20
Area - 6x4=24