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3 years ago

4.88 to nearest tenths

Mathematics

2 answers:

bazaltina [42]3 years ago

7 0

Answer:

4.9

Step-by-step explanation:

4.88

The first after the period is the tenths place, it is rounded up to 4.9

Arte-miy333 [17]3 years ago

7 0

It would be 4.9 because the 8 is bigger than 5

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-5+7q+ -5q+ -9q please help

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For this case we must simplify the following expression

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So, rewriting the expression we have:

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$\begin{gathered} A=\frac{\theta}{360\degree}\times\pi r^2 \\ Where\text{ r}=AB=6\text{ units} \\ A=9\pi\text{ square units} \end{gathered}$

Substitute the values of the variables into the formula above to find the angle, θ, subtended by the sector.

$\begin{gathered} 9\pi=\frac{\theta}{360\degree}\times\pi\times6^2 \\ Crossmultiply \\ 9\pi\times360=36\pi\times\theta \\ 3240\pi=36\pi\theta \\ Divide\text{ both sides by 36}\pi \\ \frac{3240\pi}{36\pi}=\frac{36\pi\theta}{36\pi} \\ 90\degree=\theta \\ \theta=90\degree \end{gathered}$

To find the length of the arc, s, the formula is

$\begin{gathered} s=\frac{\theta}{360\degree}\times2\pi r \\ Where \\ \theta=90\degree \\ r=6\text{ units} \end{gathered}$

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Hence, the length of the arc, s, is 3π units.

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