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VikaD [51]
3 years ago
5

Jasper needs 180 of string for his project how many yards did he buy.

Mathematics
1 answer:
andrew-mc [135]3 years ago
3 0

Answer:

5 yards

Step-by-step explanation:

The measurements of the 180 should be Inches

Length of string Jasper needs = 180 inches

how many yards did he buy?

1 yard = 36 inches

Number of yards he needs = Length of string Jasper needs / inches per yard

= 180 inches / 36 inches

= 5 yards

Number of yards he needs = 5 yards

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Factor the trinomial x^2 - 7x + 10
Valentin [98]

Answer:

(x-5) (x-2)

Step-by-step explanation:

x^2 (-2x-5x) +10

basically you will write the equation down and then to double check multiply the x and then the -5 into (x-2). this can be repetitive if you get it wrong so try to do numbers that make sense.

7 0
3 years ago
To increase an amount by 5% what single multiplayer would u use? PLZ HELP!!
bezimeni [28]
You can use times the value by 1.05 to find the answer directly
5 0
3 years ago
What is the perimeter of rhombus LMNO? 20 units 24 units 40 units 48 units
NeTakaya
The little lines on each side of the rhombus mean that all the sides are the same length.

We can set line LM and MN equal to solve for X, then we can solve the length of a side.

3x-3 = x+7

Add 3 to each side:
3x = x +10

Subtract x from each side:

2x = 10

Divide both sides by 2:
x = 10/2
x = 5

Now we have the value for x, replace x in one of the side formulas:

x +7 = 5+7 = 12

Each side = 12 units.

 The perimeter would be 12 + 12 + 12 + 12 = 48 units.



3 0
3 years ago
Read 2 more answers
In the standard (x, y) coordinate plane, what is the distance, in coordinate units, between (-3, -2) and (5, 5)?
Sav [38]

Answer:

10.630

Step-by-step explanation:

\sqrt(x_{2}  -x_{1})^{2} + (y_{2} -y_{1})^{2}

\sqrt( 5-(-3)^{2} + (5- (-2)^{2}

(5 - ( - 3)^2 = 64

(5 - ( -2)^2 = 49

49 + 64

113

\sqrt113

10.630


I hope this helps

8 0
3 years ago
Los dueños de un restaurante cultivan sus propios
hammer [34]

Answer:

Quedan 2.083 m^3 de agua en el reservorio.

Equivalen a 2083 litros.

Step-by-step explanation:

Los dueños del restaurante tienen un reservorio de agua cuyo volumen es de 6.25 m^3.

Si han utilizado 2/3 del reservorio, esto implica que aún quedan en el reservorio una tercera parte del volumen original (1/3).

Entonces, la cantidad de metros cúbicos (m^3) de agua que quedan en el reservorio se puede calcular como:

V=(1/3)\cdot V_0=(1/3)\cdot6.25\,m^3=2.083\,m^3

Este valor equivale a un volumen en litros de:

V=2.083\,m^3\cdot \dfrac{1,000\,l}{1m^3}=2,083\,l

7 0
3 years ago
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