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amm1812
3 years ago
14

How fast can he jog?

Mathematics
1 answer:
Hitman42 [59]3 years ago
3 0
10 minutes nothing else
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Which of the following represents a function with the greatest rate of change?
defon
So the rate of change can be found in different places.

For the first one:

This equation is in slope-intercept form, or y = mx + b.

m would be the slope/rate of change, and b the y intercept. (x and y would just be any sets of ordered pairs that fit into the equation.)

So if you look at which number is in the m spot, or the rate of change spot, you see that 5 is the rate of change.

For the second one: The formula for slope is:

m = \frac{ y_{2} -  y_{1} }{x_{2} -  x_{1} }

So just put in any ordered pairs in. I'm just going to put in the ordered pairs, (6, 30) and (4, 22).

Or,

m = (30 - 22) / (6 - 4)

Or,

m = 8/2

Or 4.

For the third one:

You can use the same formula as I stated above.

So you have to look for two ordered pairs here, two points.

So you can estimate that two of the points are: (0, 3) and (-2, -9).

So then just solve for that.

(-9 - 3) / (-2 - 0) = -12 / -2 = 6

For the last one:

Again, use the same equation.

m = (7 - 1) / (-1 - (-3))

 m = 6/2 

m = 3

So the one with the greatest rate of change would be C.
5 0
3 years ago
Read 2 more answers
Use the graph to find out over what interval f(x) is less than or equal to 0. PLEASE HELP ASAP!!!
jok3333 [9.3K]

Answer:

[-5, 2]

Step-by-step explanation:

We have to find the interval for which f(x) <= 0, the interval is [-5, 2].

5 0
3 years ago
Which figure has the same area as the parallelogram shown below? A. A triangle with a base of 4 mm and a height of 20 mm B. A tr
Arisa [49]
<h2>Answer:  A trapezoid with bases of 6 mm and 14 mm and a height of 8 mm </h2>

The parallelogram in the figure has an area of 80mm^{2}, according to the following formula, which works for all rectangles and parallelograms:

A_{parallelogram}=(b)(h)   (1)

Where b is the base and h is the height

The<u> area of a triangle</u> is given by the following formula:

A_{triangle}=\frac{1}{2}(b)(h)   (2)

So, for option A:

A_{triangle}=\frac{1}{2}(4mm)(20mm)=40mm^{2} \neq 80mm^{2}    

Now, the <u>area of a trapezoid </u>is:

A_{trapezoid}=\frac{1}{2}(b_{1}+ b_{2})(h)   (3)

For option B:

A_{trapezoid}=\frac{1}{2}(15mm+25mm)(2 mm)=40mm^{2} \neq 80mm^{2}    

For option C:

A_{trapezoid}=\frac{1}{2}(6mm+14mm)(8 mm)=80mm^{2}>>>>This is the correct option!

For option D:

A_{rectangle}=(30mm)(8mm)=240mm^{2} \neq 80mm^{2}    

<h2>Therefore the correct option is C</h2>
5 0
3 years ago
4= -2(x-2) +4 please help I’ll give you points!
Elina [12.6K]
<h3>Solution:</h3>

4 = -2(x-2) + 4

or, 4 = -2x + 4 + 4

or, 4 = -2x + 8

or, 4 - 8 = -2x

or, -4 = -2x

or, -4/-2 = x

or, 2 = x

<h2>Answer:</h2>

The value of x is 2.

4 0
3 years ago
Read 2 more answers
I need the answer of this with steps and solutions fast plz​
Natali [406]

Answer:

1 \dfrac{13}{15}

Step-by-step explanation:

2 \dfrac{1}{5} - \dfrac{1}{3} =

= \dfrac{11}{5} - \dfrac{1}{3}

= \dfrac{33}{15} - \dfrac{5}{15}

= \dfrac{28}{15}

= 1 \dfrac{13}{15}

6 0
3 years ago
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