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2 years ago

Eva is solving the equation 4(x+32)=8

Mathematics

1 answer:

Luba_88 [7]2 years ago

8 0

Answer:

The correct answer is -30

Step-by-step explanation:

4(x+32)=8 basically you multiply 4 times the numbers that are in the parentesis which that will equals to 4x+128 because 4x1= 4x and 4x32 = 128. then you subtract 128 from 8 which equals to -120. you divide -120 by 4 which equals to -30.

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mrs. West took her class on a field trip to the museum cost of admission for the girls was $90 and the cost of admission for the

timofeeve [1]

Answer:

15 dollars

Step-by-step explanation:

4 0

3 years ago

Please help, thank you!

shutvik [7]

65 x6 = 390
80 x 3= 240

390+240 = 630

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2 years ago

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Which is the largest number?<br> ОА. 1.9x 106<br> ОВ. 2.5 x 105<br> Ос. 8.7 x 102<br> OD. 5.8 x 103

DanielleElmas [232]

C. 8.7 x 102

8.7 x 102= 887.4
Which is the largest product out of all the other equations.

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4 0

3 years ago

Read 2 more answers

G(x) = -3/2x-9, if G(x) = -48, find x

Svetlanka [38]

Answer:

x=26

Step-by-step explanation:

first rewrite the problem since u know that G(x)=-48

-48=-3/2x-9

second you want to add the 9 to -48 which gives u -39

-39=-3/2x

third you want to times the reciprocal so it would be

-2/3 times -39/1

u can cross out the negatives and turn them into a positive

fourth you can cross cancel 3 and 39 which now the problem looks like this

2/1 times 13/1

which you would times 2 and 13 which your answer would be

6 0

3 years ago

The graph of a quadratic function passes through the points (-1,0), (-2,0), and (0,2). Write the quadratic function in general f

ddd [48]

Answer:

$f(x)=x^2+3x+2$

Step-by-step explanation:

step 1

we have the points

(-1,0), (-2,0), and (0,2)

Plot the points

using a graphing tool

see the attached figure

The graph of a quadratic function must be a vertical parabola open upward

The vertex is a minimum

The quadratic function in general form is equal to

$f(x)=ax^2+bx+c$

Substitute the value of x and the value of y of each given ordered pair in the general equation and solve for a,b and c

(0,2)

For x=0, y=2

substitute

$2=a(0)^2+b(0)+c$

$c=2$

(-1,0)

For x=-1, y=0

substitute

$0=a(-1)^2+b(-1)+2$

$0=a-b+2$ ----> $a=b-2$ ----> equation A

(-2,0)

For x=-2, y=0

substitute

$0=a(-2)^2+b(-2)+2$

$0=4a-2b+2$ ----> equation B

we have the system

$a=b-2$ ----> equation A

$0=4a-2b+2$ ----> equation B

substitute equation A in equation B

$0=4(b-2)-2b+2$

solve for b

$0=4b-8-2b+2$

$2b=6$

$b=3$

Find the value of a

$a=3-2=1$

therefore

The quadratic function in general form is equal to

$f(x)=x^2+3x+2$

see the attached figure N 2 to better understand the problem

7 0

3 years ago