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AleksAgata [21]
3 years ago
7

A cornbread recipe calls for 2 eggs to make 15 servings. how many eggs are needed to make 45 servings? (i think its 6)

Mathematics
1 answer:
vladimir1956 [14]3 years ago
4 0
You thought right.
if 2 eggs make 15 servings then:
4 eggs make 30 servings and
6 eggs make 45 servings
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A square garden is 50 inches long on each side.What is the length of the perimeter in feet?
leva [86]

Answer:

50/3 feet

Step-by-step explanation:

A square has 4 equal sides, so the perimeter is 4*50, or 200 inches.

But we want the answer in feet. There are 12 inches in a foot, so the perimeter in feet is 200/12 or 50/3 feet.

5 0
3 years ago
Me ajudem com a 3º questão
Alisiya [41]

I can't read that language but I'll guess it says write a second degree equation then solve for n when d=10.

10 = \dfrac{n(n-3)}{2}

20 = n^2 - 3n

n^2 - 3n - 20 = 0

Answer: n² - 3n - 20 = 0

That doesn't factor so there is no integer n solution.

That means there are no polygons with 10 diagonals.

n = \frac 1 2(3 \pm \sqrt{89})

7 0
3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
T is between points D and S. DT = 27 and TS = 35.
lana [24]
D                  T                          S
|-------27---------|
                     |------------35-----------|
DS=27+35=62
the answer is 62
7 0
3 years ago
Read 2 more answers
HELP please please please please​
svetlana [45]

Answer:

Step-by-step explanation:

5.577

4 0
3 years ago
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