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Lilit [14]
2 years ago
9

Serika has hired Tom to build her a dollhouse. The dollhouse will be a scale model of her home, and the scale will be 2 inches :

Mathematics
1 answer:
sveticcg [70]2 years ago
7 0

Answer:

96 square inches

Step-by-step explanation:

The scale is 2 inches : 3 feet

Thus for 18 feet in Serika's real house, the model is 18 * (2"/3') = 12 inches

For 12 feet in Serika's real house, the model is 12 * (2"/3') = 8 inches

Area of carpeting needed in Serika's dollhouse = 12" * 8" = 96 square inches

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Identify the correct corresponding parts
andrey2020 [161]

Answer:

The correct corresponding part is;

\overline {CB} ≅ \overline {CD}

Step-by-step explanation:

The information given symbolically in the diagram are;

ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)

Segment \overline {CA} is congruent to \overline {CE} ( \overline {CA} ≅ \overline {CE})

Segment \overline {CB} is congruent to \overline {CD} ( \overline {CB} ≅ \overline {CD})

From which, we have;

∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∠B ≅ ∠D by CPCTC

Segment \overline {AB} is congruent to \overline {DE} (\overline {AB} ≅ \overline {DE}) by CPCTC

Segment \overline {AE} bisects \overline {BD}

Segment \overline {BD} bisects \overline {AE}

Therefore, the correct option is \overline {CB} ≅ \overline {CD}

3 0
3 years ago
During the mayoral election,two debates were held between the candidates. The first debate lasted 1 2/3 hours.The second one was
butalik [34]

Answer:

2nd debate was 3 hours long.

Step-by-step explanation:

We have been given that during the mayoral election,two debates were held between the candidates. The first debate lasted 1 2/3 hours. The second one was 1 4/5 times as long as the first one.

Let us find the estimate of time spent on 2nd debate.

1 2/3 hours would be approximately 2 hours. 1 4/5 times would be equal to 2 times.

2*2=4

Therefore, the estimated time is less 4 hours.

To find the time spent on 2nd debate, we will multiply 1 2/3 by 1 4/5.

First of all, we will convert mixed fractions into improper fractions as:

1\frac{2}{3}=\frac{5}{3}

1\frac{4}{5}=\frac{9}{5}

Now, we will multiply both fractions as:

\frac{5}{3}\times \frac{9}{5}

\frac{1}{3}\times \frac{9}{1}

\frac{9}{3}\Rightarrow 3

Therefore, the 2nd debate was 3 hours long.

5 0
3 years ago
Can someone please help me?
Pavlova-9 [17]

Answer:

A.1/12

Step-by-step explanation:

Probability of the card being yellow is 1/4

And probability of the card being even is 1/3

And if you are asked to find a yellow even card we multiply those two numbers to get 1/12

3 0
3 years ago
Read 2 more answers
In this exercise, T: R2 → R2 is a function. For each of the following parts, state why T is not linear. (a) T(a1, a2)= (1, a2) (
DENIUS [597]

Answer:

  • a) T is not homogeneous
  • b) T is not additive
  • c) T is not homogeneous
  • d) T is not additive
  • e) T is not additive

Step-by-step explanation:

In each case there is an example where one property of linear functions fails.

  • a) T(2(1,0))=T((2,0))=(1,0); 2T((1,0))=2(1,0)=(2,0). These vectors are not equal, then T doesn't satisfy the condition of scalar multiplication (homogeneity).
  • b) T((1,2)+(2,3))=T(3,5)=(3,9); T((1,2))+T((2,3))=(1,1)+(2,4)=(3,5). Because these vectors are not equal, T doesn't satisfy the property of vector addition (additivity).
  • c) T(\frac{1}{2}(\pi,0))=T((\frac{\pi}{2},0))=(\sin(\frac{\pi}{2}),0)=(1,0); \frac{1}{2}T((\pi,0))=\frac{1}{2}(0,0)=(0,0) so T is not homogeneous.
  • d) T((-1,0)+(1,0))=T(0,0)=(0,0); T((-1,0))+T((1,0))=(1,0)+(1,0)=(2,0) then T is not additive.
  • e) T((0,0)+(1,0))=T(1,0)=(2,0); T((0,0))+T((1,0))=(1,0)+(2,0)=(3,0) then T is not additive.
8 0
3 years ago
I need help again... 4x divided by 8 = 3
iogann1982 [59]
X=6.0000000000000000000
3 0
3 years ago
Read 2 more answers
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