Find the halfway point between endpoints A (6,-9) and B (-6,-5). (x1+x22 , y1+y22)
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Answer:
Therefore the dimension of the cuboid is 8 inches×4 inches ×6 inches.
Step-by-step explanation:
Cuboid : A cuboid is a three dimension shape. The length ,breadth and height of a cuboid are not same.
- A cuboid has 6 faces.
- A cuboid contains 8 vertices.
- A cuboid contains 12 edges .
- The total surface area of a cuboid is
= 2(length×breadth+breadth×height+length×height) square units
- The dimension of a cuboid is written as length×breadth×height.
- The volume is( length×breadth×height) cubic units
Given that the volume of the box is 192 cubic inches.
Let x inches be the width of the cuboid.
Since the length is twice as long as its width.
Then length = 2x inches
Again height is 2 inches longer than width.
Then height = (x+2) inches.
Therefore the volume of the cuboid is
cubic inches
cubic inches
cubic inches
According to the problem,
Therefore x=4
Since the all zeros of x²+6x+24 =0 is negative.
Therefore breadth = 4 inches
length=(2×4) inches=8 inches
and height = (4+2)inches = 6 inches.
Therefore the dimension of the cuboid is 8 inches×4 inches ×6 inches.