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Gelneren [198K]
3 years ago
15

Find the halfway point between endpoints A (6,-9) and B (-6,-5). (x1+x22 , y1+y22)

Mathematics
1 answer:
Ierofanga [76]3 years ago
8 0

Answer:

.

Step-by-step explanation:

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Can we conclude that these two triangles are congruent?
Aleonysh [2.5K]

Answer:

Yes,

Step-by-step explanation:

because two sides are shown equal to each other, a and b. Also two angles are equal to each other, x and y. Once you know two angles or two sides are equal so is the third side.

Another way is SAS (side angle side). There is side a, angle y, and side b. These are shown on both triangles.

Therefore, we can conclude these two triangles are congruent.

5 0
3 years ago
HEY CAN ANYONE HELP ME PLZ
Nataly [62]

Answer:

2/7 is correct answer

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3 years ago
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Please help solve algebra question
Ksenya-84 [330]
Let be:Speed of the wind: WSpeed of the plane in still air: P
Against the wind the plane flew:Distance: d=175 milesTime: ta=1 hour 10 minutesta=1 hour (10 minutes)*(1 hour/60 minutes)ta=1 hour + 1/6 hourta=(6+1)/6 hourta=7/6 hourSpeed against the wind: Sa=d/taSa=(175 miles) / (7/6 hour)Sa=175*(6/7) miles/hourSa=1,050/7 miles per hourSa=150 mph
(1) P-W=Sa(1) P-W=150
The return trip only took 50 minutesDistance: d=175 milesTime: tr=50 minutestr=(50 minutes)*(1 hour/60 minutes)tr=5/6 hour
Speed retur trip: Sr=d/trSr=(175 miles) / (5/6 hour)Sr=175*(6/5) miles/hourSr=1,050/5 miles per hourSr=210 mph
(2) P+W=Sr(2) P+W=210
We have a system of 2 equations and 2 unknows:(1) P-W=150(2) P+W=210
Adding the equations:P-W+P+W=150+2102P=360Solving for P:2P/2=360/2P=180
Replacing P by 180 in equation (2):(2) P+W=210180+W=210
Solving for W:180+W-180=210-180W=30
Answers:The speed of the plane in still air was 180 mphThe speed of the wind was 30 mph
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3 years ago
11. There are a total of 30 puzzle pieces. Three
natulia [17]

Answer: 2

Step-by-step explanation:

5-3=2

30-5=15

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Scalene,Acute i think it is haha
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