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3 years ago

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The total cost for a bucket of popcorn and 4 movie tickets is $56. The total cost for the same size bucket of popcorn and 6 movi

e tickets is $80. The cost of a bucket of popcorn is $8. Which equation represents the relationship between y, the total cost of the popcorn and movie tickets, and x, the number of movie tickets that are purchased?
y = 12x + 8
y = 12x − 8
y = 14x + 8
y = 14x − 8 Will give brainlliest

1 answer:

timurjin [86]3 years ago

5 0

Answer:

y = 12x + 8

Step-by-step explanation:

56 - 8 = 48

48/12 is possible therefore its 1

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Use the arithmetic sequence of numbers 1, 3, 5, 7, 9,.to find the following:

Rasek [7]

$a)\\\\
a_{n+1}-a_n=d\\
for\ n=1\\
a_2-a_1=d\\
d=3-1=2\ - difference\ between\ two\ consecutive\ terms\\\\
b)\\
a_n=a_1+(n-1)d\\
n=101\\
a_{101}=1+(101-1)*2\\
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c)\\
Sn=\frac{a_1+a_n}{2}*n\\
n=20\\
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3 years ago

YALL NEVER ANSWER AH POOP plz help

lakkis [162]

Answer:

The given point A (6,13) lies on the equation. True

The given point B(21,33) lies on the equation. True

The given point C (99, 137) lies on the equation. True

Step-by-step explanation:

Here, the given equation is : $y =\frac{4}{3} x + 5$

Now,check the given equation for the given points.

1) A (6,13)

Substitute x = 6 in the given equation $y =\frac{4}{3} x + 5$

$y =\frac{4}{3} (6) + 5 = 4(2) + 5 = 8 + 5 = 13$

⇒ y= 13

Hence, the given point A (6,13) lies on the equation.

2) B (21,33)

Substitute x = 21 in the given equation $y =\frac{4}{3} x + 5$

$y =\frac{4}{3} (21) + 5 = 4(7) + 5 = 28 + 5 = 33$

⇒ y = 33

Hence, the given point B(21,33) lies on the equation.

3) C (99, 137)

Substitute x = 99 in the given equation $y =\frac{4}{3} x + 5$

$y =\frac{4}{3} (99) + 5 = 4(33) + 5 = 132 + 5 = 137$

⇒ y = 137

Hence, the given point C (99, 137) lies on the equation.

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3 years ago

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adoni [48]

I think its 44. The amount of people increase by 12 every time you add more subs. Hope that helps!

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3 years ago

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A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. Th

Olegator [25]

Answer:

(a) 74553

(b) 172120

(c) 234802

Step-by-step explanation:

Given

$y = \frac{340110}{1 + 377e^{-0.259t}}$

Solving (a): 1998

Year 1998 means that:

$t =1998 - 1980$

$t =18$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*18}}$

$y = \frac{340110}{1 + 377e^{-4.662}}$

$y = \frac{340110}{1 + 3.562}$

$y = \frac{340110}{4.562}$

$y = 74553$ --- approximated

Solving (b): 2003

Year 2003 means that:

$t = 2003 - 1980$

$t =23$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*23}}$

$y = \frac{340110}{1 + 377e^{-5.957}}$

$y = \frac{340110}{1 + 0.976}$

$y = \frac{340110}{1.976}$

$y = 172120$ --- approximated

Solving (c): 2006

Year 2006 means that:

$t = 2006 - 1980$

$t =26$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*26}}$

$y = \frac{340110}{1 + 377e^{-6.734}}$

$y = \frac{340110}{1 + 0.4485}$

$y = \frac{340110}{1.4485}$

$y = 234802$ --- approximated

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2 years ago

Make r the subject of the formula <br>v = \pi \: h {}^{2}(r - \frac{h}{3})v=πh2(r−3h) <br>

mel-nik [20]

Answer:

$\boxed{r = \frac{h}{3} + \frac{v}{\pi {h}^{2} } }$

Step-by-step explanation:

$Solve \: for \: r: \\ = > v= \pi {h}^{2}(r - \frac{h}{3} ) \\ \\ v=\pi {h}^{2}(r - \frac{h}{3} )is \: equivalent \: to \: {h}^{2}\pi(r - \frac{h}{3} ) = v: \\ = > {h}^{2}\pi(r - \frac{h}{3} ) = v \\ \\ Divide \: both \: sides \: by \: \pi {h}^{2} : \\ = > r - \frac{h}{3} = \frac{v}{\pi {h}^{2} } \\ \\ Add \: \frac{h}{3} \: to \: both \: sides: \\ = > r = \frac{h}{3} + \frac{v}{\pi {h}^{2} }$

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2 years ago