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3 years ago

What is the wavelength of the third harmonic in a 4.5-m-long pipe that is closed at one end?

Physics

1 answer:

lisov135 [29]3 years ago

5 0

Answer:

Wavelength of sound in the pipe is 6.0 m

Explanation:

As we know that closed pipe is given to us so here at open end it will form antinode while at closed end it will form Node

Here we know that in closed pipes on odd harmonics will exist

so here for third harmonic we have

$L = \frac{\lambda}{4} + \frac{\lambda}{2}$

where L = length of the pipe

so we have

$4.5 = \frac{3\lambda}{4}$

$\lambda = 6.0 m$

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2 years ago

2 kg and 3 kg objects slide together, and then they break apart. If the final velocity of 2 kg is 10 m/s,

lara [203]

Answer:

P = (2 + 3) * V where V is their initial speed (total momentum)

P = 2 * 10 + 3 * Vx where Vx here would be V3

If the initial momentum is not known how can one determine the final velocity of the 3 kg obj.

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3 years ago

A 1.00 kg object moving in the + x direction at 10.0 m/s collides with a 1.50 kg object traveling at 5.00 m/s in the - x directi

marysya [2.9K]

Answer:

The amount of kinetic energy lost during the collision is 60.75 J

Explanation:

The given parameters are;

The mass of the object moving in the +x direction, m₁ = 1.00 kg

The velocity of the object moving in the +x direction, v₁ = 10.0 m/s

The mass of the object moving in the -x direction, m₂ = 1.50 kg

The velocity of the object moving in the +x direction, v₂ = 5.00 m/s

The final velocity of the 1.00 kg mass after collision, v₃ = 4.00 m/s

The direction of motion of the 1.00 kg mass after collision = -x direction

The total initial kinetic energy of the system, $K.E._{total \ initial}$ = 1/2·m₁·v₁² + 1/2·m₂·v₂²

∴ $K.E._{total \ initial}$ = 1/2×1.00×10² + 1/2×1.50×5² = 68.75 J

The final kinetic energy of the system, $K.E._{final}$ = 1/2·m₁·v₃²

$K.E._{final}$ = 1/2×1.00×4² = 8 J

The amount of kinetic energy lost during the collision, $\Delta K.E._{system}$ is given as follows;

$\Delta K.E._{system}$ = $K.E._{final}$ - $K.E._{total \ initial}$ = 8 J - 68.75 J = -60.75 J

The amount of kinetic energy lost during the collision = 60.75 J.

7 0

3 years ago