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Rus_ich [418]
3 years ago
11

What tripositive ion has the electron configuration [kr] 4d3 ? what neutral atom has the electron configuration [kr] 5s 2 4d2 ?

Physics
1 answer:
tigry1 [53]3 years ago
6 0

(a)

Electronic configuration is given as follows:

[Kr]4d^{3}

Since, this is the electronic configuration of ion with+3 that means 3 electrons are removed. On adding the 3 electrons, the electronic configuration of neutral atom can be obtained.

Thus, electronic configuration of neutral atom is [Kr]4d^{5}5s^{1}.

The atomic number of Kr is 36, thus, total number of electrons become 36+6=42.

This corresponds to element: molybdenum. Thus, the tripositive atom will be Mo^{3+}.

(b) The given electronic configuration is [Kr]5s^{2}4d^{2}.

The atomic number of Kr is 36, thus, total number of electrons become 36+4=40.

This corresponds to element zirconium, represented by symbol Zr.

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Shrinking Loop. A circular loop of flexible iron wire has an initial circumference of 167 cm , but its circumference is decreasi
PSYCHO15rus [73]

Answer:

a)     fem = - 0.0103 V,  b) the applied field is in a vertical upward direction, the induced current is clockwise.

Explanation:

a) For this exercise we use Faraday's law

         fem =  - \frac{d \phi}{dty}

   

the magnetic flux is

         Ф = B. A = B A cos θ

The bold letters indicate vectors, in this case the direction of the magnetic field and the normal to the circumference is parallel therefore the angle is zero and the cos 0 = 1

         fem = - B dA / dt

the area of ​​a circle is

        A = π r²

l

et's perform the derivative

         dA / dt =π 2r \frac{dr}{dt}

we substitute

          fem = - B 2π r \frac{dr}{dt}

the circumference of a circle is

         L = 2π r

we substitute

          fem = - B L  ( L  )

          fem =  

Let's find the circumference for the 9 s, let's use a direct rule of proportions

If the circumference changes 13cm at t = 1. how much does it change at t=9s

         ΔL = 13cm (9s / 1s) = 117cm

the circumference that is

        L = Lo - ΔL

        L = 167 - 117

        L = 50 cm

let's reduce all magnitudes to the SI system

         L = 0.50 m

          = 0.130 m / s

calculate us

         fem = - 1.00 0.50 0.130

         fem = - 0.0103 V

b) the electromotive force induced in the opposite direction to the change of the radius and is decreasing with time, the current follows the direction of the decreased voltage therefore the current is induced in the opposite direction to the change of the magnetic flux.

If the applied field is in a vertical upward direction, the induced current is clockwise.

3 0
3 years ago
A minivan is tested for acceleration and braking. In the street-start acceleration test, the elapsed time is 8.6 s for a velocit
Varvara68 [4.7K]

The question is incomplete. Here is the complete question:

A minivan is tested for acceleration and braking. In the street-start acceleration test, the elapsed time is 8.6 s for a velocity increase from 10 km/h to 100 km/h. In the braking test, the distance traveled is 44 m during braking to a stop from 100 km/h. Assume constant values of acceleration and deceleration. Determine  

(a) the acceleration during the street-start test,  

(b) the deceleration during the braking test.

Answer:

(a) 37500 km/h²

(b) 113636.36 km/h²

Explanation:

part (a)

Because it is given that we can assume constant acceleration therefore we can use the following equation of motion:

<em>v = u + (a)(t) </em>

where <em>v </em>is final velocity, <em>u </em>is initial velocity, <em>a </em>is acceleration and <em>t </em>is time change

Given in the question:

v = 100km/h

u = 10 km/h

t = 8.6 sec (changing to hours)

t = 0.0024 hours (round off to 4 decimal places)

100 = 10 + (a x 0.0024)

Rearranging the equation to find value of a

a = (100 – 10) / 0.0024

a = 37500 km/h² (Answer)

part (b)

Now we can use the following equation to find deceleration

<em>2(a)(s) = v² – u²</em>

Where a is acceleration, s is distance travelled, v is final velocity and u is initial velocity

Given in the question

s = 44 m

changing to km

s = 0.044 km

v = 0 km/h (because it stops)

u = 100 km/h

2(a)(0.044) = (0)² – (100)²

0.088(a) = 0 - 10000  

a = - 10000/0.088

a = - 113636.36 km/h2  

The negative sign in the answer shows that it is deceleration

Therefore deceleration = 113636.36 km/h² (Answer)

6 0
3 years ago
How does temperature influence the appearance of a star? Give an example in your response.
loris [4]

The cooler the temp of the star the star would appear to glisten a red. if the star is warmer the star would be a light blue or blue. An example would be the tiny red dwarf stars. they only have 7% of the suns heat so they appear red.

5 0
3 years ago
How is the energy carried per photon of light related to the wavelength of the light?
AveGali [126]

The energy carried per photon of light is inversely proportional to the wavelength of the light

The "quantum of electromagnetic radiation" is called a photon. It is, thus, the tiniest and most basic particle of electromagnetic radiation. A photon is a stable particle that has no mass and no electric charge. The concept of wave-particle duality holds true for this particle.

The distance between the two crests or troughs of the light wave is known as the wavelength of light. It is represented by the greek letter lambda 'λ'

A quantity is inversely proportional if it decreases when the related quantity is increased or vice versa. For example, frequency is inversely proportional to wavelength

To know more about photons, refer to here

brainly.com/question/20912241

#SPJ4

3 0
2 years ago
A dog runs down his driveway with an initial speed of 5 m/s for 8 s, and then uniformly increases his speed to 10 m/s in 5 s.
MakcuM [25]
Acceleration is given by change in velocity divided by change in time, so his acceleration should just be (10-5)/5 which is [tex] \frac{5}{2} \frac{m}{s^{2}} [tex]

The driveway is 40 meters plus 225/4. You can do the math.
8 0
3 years ago
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