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Kisachek [45]
3 years ago
13

Does anyone know how to do this? please help me

Mathematics
2 answers:
Elis [28]3 years ago
8 0
On the x column, you would write 1, 2, 3, 4, and so on. Then, in the y box, you plug in that number into the equation. Write your answer in the y column. 

For example, if x = 1, then 1^2 + 2 - 8 = - 5. 
If x = 1, y= -5
e-lub [12.9K]3 years ago
6 0
Since we have 7 spaces lets use 1,2,3,4,5,6, and 7 for x:

y=1^2+2x-8
y=1+2-8
y=-5

y=2^2+4-8
y=8-8
y=0

y=3^2+6-8
y=15-8
y=7

y=4^2+8-8
y=16

y=5^2+10-8
y=27

y=6^2+12-8
y=40

y=7^2+14-8
y=49+14-8
y=49+6
y=55

The completed chart:
x | y
1 | -5
2 | 0
3 | 7
4 | 16
5 | 27
6 | 40
7 | 55





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4 years ago
What is the area of this whole figure in square units?
IrinaK [193]
Well, it is a good and interesting question

Such areas could be calculated in a single shoot and also by dividing the whole shape into other shapes and the total area would be the sum of these areas

I prefer the way of a single shoot ...

The figure represents a trapezoid:
its lower base = 21 units
its upper base = 12 units
the normal height between them = 8 units

NOW

The area of a trapezoid = [(sum of bases' lengths) ÷ 2] * height
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Hope that helps
7 0
3 years ago
Janet can do a job in 3 hours, and Garry can do the same job in 2 hours. If Janet works for 1 hour before Garry comes to help, h
lidiya [134]

Answer:

48 minutes

Step-by-step explanation:

Given that:

Time taken by Janet = 3 hours

Janet's rate = 1/3 job / hour

Time taken by Garry = 2 hours

Garry's rate = 1/2

Rate of working together :

1/3 + 1/2 = (2 + 3) /6 = 5/6 job/hour

If Janet works for one hour before Garry joins ;

1/3 of the job has been done by Janet

1 - 1/3 = 2/3 of the job left

Hence to finish the job together, it will take :

Fraction of JOB left ÷ rate of working together

(2/3 ÷ 5/6)

= 2 /3 * 6/5

= 12 / 15

= 4 / 5 hours

To minutes

(4/5) * 60

= 240/5

= 48 minutes

8 0
3 years ago
Read 2 more answers
The table represents a linear function.
Illusion [34]

Answer:

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Step-by-step explanation:

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