All categories

2 years ago

Find the gradients of lines A and B.

Mathematics

1 answer:

Tanya [424]2 years ago

3 0

Let's see

For line A

(2,2)
(3,6)

Slope

m=6-2/3-2
m=4/1
m=4

For line B

(1,6)
(2,4)

Slope

m=4-6/2-1
m=-2/1
m=-2

You might be interested in

What is the solution to the system of equations below?

Lemur [1.5K]

I think the answer is a

8 0

3 years ago

The time X it takes Hattan to drive to work on a randomly selected day follows a distribution that is approximately Normal with

alexdok [17]

Answer:

Shape: Approximately Normal

Center: 20 minutes

Variability: 6.5 minutes.

4 0

3 years ago

Which value of x is the solution to the equation. -2 - 4x = 14

dusya [7]

Answer:

The answer is C or x=-4.

Step-by-step explanation:

I hope this helps!

8 0

3 years ago

I NEED HELP AGAIN YALL

ludmilkaskok [199]

Answer:

y = 3x + 2

Step-by-step explanation:

First you want to know what the slope intercept form is. y = mx + b. Now take two points from the table and put them in the equation and get the slope of 3. Now we have y = 3x + b. To find b we need to plug in any point into the equation. I chose (-1, -1). -1 = 3(-1). Solve and you get 2. Now we are left with y = 3x + 2

6 0

3 years ago

Read 2 more answers

The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room

Alexandra [31]

Answer:

$\bar x = 260.1615$

$\sigma = 70.69$

The confidence interval of standard deviation is: $53.76$ to $103.25$

Step-by-step explanation:

Given

$n =20$

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}$

$\bar x = \frac{5203.23}{20}$

$\bar x = 260.1615$

$\bar x = 260.16$

Solving (b): The standard deviation

This is calculated as:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}$ $\sigma = \sqrt{\frac{94938.80}{19}}$