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2 years ago

Find the gradients of lines A and B.

Mathematics

1 answer:

Tanya [424]2 years ago

3 0

Let's see

For line A

(2,2)
(3,6)

Slope

m=6-2/3-2
m=4/1
m=4

For line B

(1,6)
(2,4)

Slope

m=4-6/2-1
m=-2/1
m=-2

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You need 320 mL of a 85% alcohol solution. On hand, you have a 60% alcohol mixture. How much of the 60% alcohol mixture and pure

Radda [10]

Answer:

Step-by-step explanation:

If we let x = the amount of 5% solution and y = the amount of pure alcohol, we can set up that

.05x+y is the amount of alcohol in our resulting mixture, and x+y is the total amount in our resulting mixture (which we know is 380)

so we also know that:

(.05x+y)/380 = .6

If we simplify this we come up with:

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3 years ago

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tester [92]

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Step-by-step explanation:

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3 years ago

Audrey is buying a new car for $32,998 she plans to make a down payment of $4200 if she makes monthly payment of $225 for the ne

marta [7]

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2 years ago

Which equation represents an exponential function with an initial value of 500? f(x) = 100(5)x f(x) = 100(x)5 f(x) = 500(2)x f(x

Evgen [1.6K]

Answer:

The answer is

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2020

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3 years ago

Read 2 more answers

Suppose at a large university, 60% of the students have a Visa card and 40% of the students have a MasterCard. Also, 30% of the

Doss [256]

Answer:

0.6,0.7,0.3 neither disjoint nor independent.

Step-by-step explanation:

Given that at a large university, 60% of the students have a Visa card and 40% of the students have a MasterCard.

A= visa card

B = Master card

P(A) = 0.60 and P(B) = 0.40

P(AUB)' = 0.30

i.e. P(AUB) = 0.70

Or P(A)+P(B)-P(AB) =0.70

P(AB)= 0.30

Randomly select a student from the university.

1) the probability that this student does not have a MasterCard.

$= P(B') = 1-0.4 =0.6$

2. the probability that this student has either a Visa card or a MasterCard.

= $P(AUB) = 0.70$

3. Calculate the probability that this student has neither a Visa card nor a MasterCard.

= $P(AUB)' = 0.30$

4. Are the events A and B disjoint? Are the events A and B independent?

A and B have common prob 0.30 hence not disjoint.

P(AB) ≠P(A)P(B)

Hence not independent

6 0

3 years ago