Answer:8
Step-by-step explanation:
Recall the Maclaurin expansion for cos(x), valid for all real x :
Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives
The first 3 terms of the series are
and the general n-th term is as shown in the series.
In case you did mean cos(√(5x)), we would instead end up with
which amounts to replacing the x with √x in the expansion of cos(√5 x) :
Solving: (5)(3 - 1) + 4
Step One: Subtract 1 from 3 which is 2
<span><span>5<span>(<span>3 − 1</span>) </span></span>+ 4
Step Two, Multiply 5 by 2 which is 10</span><span>=<span><span><span>(5)</span><span>(2) </span></span>+ 4
Step Three, Add 4 to 10 which is 14</span></span><span>=<span>10+4
</span></span><span>=<span>14
Answer:
(A)14
Hope this helps!
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Y = x^2 - 6x + 7
a = 1
b = -6
c = 7
Before you get the A.O.S, you must first solve for the vertex.
The vertex formula is \frac{-b}{2a}
Plug in the numbers:
-(-6) / 2(1)
--6 = 6 and 2*1 = 2
6/2
Vertex (or x) = 3
Now you have to plug in the x in order to find the vertex (or y)
Your equation should now look like this;
y = (3)^2 - 6 (3) +7
Solve each part separately and then add it up...
3^2 = 9
-6 * 3 = -18
+7
9 - 18 + 7
A.O.S (or y) = -2
