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elena55 [62]
3 years ago
15

Solve inequality 5-3(4x-5)<32

Mathematics
1 answer:
irga5000 [103]3 years ago
6 0

Answer: x > -1

Step-by-step explanation:

1) Subtract 5 from both sides

-3(4x - 5) < 27

2) Divide both sides by -3 (Remember to change the inequality sign to face the other way, because you have multiplied/divided by a negative number)

4x - 5 > -9

3) Add 5 to both sides

4x > -4

4) Divide by 4 on both sides

x > -1

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URGENT HELP YALL WITH THIS. I WILL MARK YOU BRAINLIEST
Reptile [31]

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(9x + 17) +2 \times  ( 5x + 15 ) + (6x - 12) = 360 \\

9x + 17 + 10x + 30 + 6x - 12 = 360 \\

9x + 10x + 6x + 17 + 30 - 12 = 360 \\

Collect like terms

25x + 35 = 360

Subtract sides 35

25x + 35 - 35 = 360 - 35

25x = 325

Divide sides by 25

\frac{25x}{25}  =  \frac{325}{25}  \\

x = 13

Thus ;

RQ  \:  \: arc =2 \times (5x + 15)

RQ  \:  \: arc = 10x + 30

RQ  \:  \: arc = 10(13) + 30

RQ  \:  \: arc = 130 + 30

RQ \:  \:  arc = 160°

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7 0
2 years ago
1,023 + _____ = 1,400
denpristay [2]

Answer: 377

1,400 - 1,023 = 377

1,023 + 377 = 1,400

Step-by-step explanation: easy

5 0
2 years ago
Read 2 more answers
I need some help please. :PP
Ksivusya [100]

The answer is the third one -2.

5 0
3 years ago
Read 2 more answers
What is the sign of f on the interval -2
TEA [102]

Answer:

f is sometimes positive and sometimes negative.

Step-by-step explanation:

f(x)=(x-3)(x+2)(x+4)(x+4)(x-1)(2x-9)

Take x=-1\in(-2,\frac{9}{2})\ as-2

f(-1)=(-1-3)(-1+2)(-1+4)(-1-1)(-2-9)\\\\=(-4)(1)(3)(-2)(-11)\\\\=-264\\\\f(-1)

Take x=2\in(-2,\frac{9}{2})\ as\ -2

f(2)=(2,-3)(2+2)(2+4)(2-1)(2\times2-9)\\\\=(-1)(4)(6)(1)(-5)\\\\=120\\\\f(2)>0

Hence f(x) for x=-1 and f(x)>0 for x=2

So f is sometimes positive and sometimes negative in the interval.

3 0
3 years ago
How do I find cube roots
anyanavicka [17]

Answer:

Step-by-step explanation:

5-500 is sqare 5

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3 years ago
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