Answer:
C. The coefficient of variation is a measure of relative dispersion that expresses the standard deviation as a percentage of the mean, for any data on a ratio scale and an interval scale
Step-by-step explanation:
Th Coefficient of Variance is a measure of dispersion that can be calculated using the formula:
![CV = \frac{\sigma_{x} }{\mu_{x} } * 100%](https://tex.z-dn.net/?f=CV%20%3D%20%5Cfrac%7B%5Csigma_%7Bx%7D%20%7D%7B%5Cmu_%7Bx%7D%20%7D%20%2A%20100%25)
Where
is the Standard Deviation
and
is the sample mean
From the formula written above, it is shown that the Coefficient of Variation expresses the Standard Deviation as a percentage of the mean.
Coefficient of variation can be used to compare positive as well as negative data on the ratio and interval scale, it is not only used for positive data.
The Interquartile Range is not a measure of central tendency, it is a measure of dispersion.
Answer:
0.98386991
0.9839
Step-by-step explanation:
![\sqrt{0.968 }](https://tex.z-dn.net/?f=%20%5Csqrt%7B0.968%20%7D%20)
The answer to the question would be 455
Answer:
The entire area of the sailboat is 60cm²
Step-by-step explanation:
You can find the area of this shape by breaking it down into simpler shapes and adding up their individual areas.
In this case, the areas we'll use are the rectangle at the bottom, and the pair of triangles at the top.
Because the two triangles can be put together to form a single triangle, we don't need to measure them independently. We can simply take the total length of their bases, multiply it by their height, and divide by two. This follows the rule that the area of a triangle is equal to the area of the square that contains it divided by two.
(2cm + 3cm) × 6cm
= 5cm × 6cm
= 30cm²
The rectangle's area is of course equal to its width times its height, so we can say:
2.5cm × 12cm
= 30cm²
The total area of the shapes then is 30cm² + 30 cm², giving us a total area of 60cm²
Dividing is changed to multiplication by inverting the second fraction. So: