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olga_2 [115]
3 years ago
12

I need help with missing exponents can anyone help me

Mathematics
1 answer:
Georgia [21]3 years ago
3 0

Answer:

What is PEMDAS ?

Step-by-step explanation:

PEMDAS is an acronym. PEMDAS is an easy way to remember the math order of operations. If you look at the list of operations above, you see that the first letter of each operation in order spells PEMDAS. Here is the order of operations with the corresponding letter to spell PEMDAS:

P: PARENTHESIS

E: EXPONENTS

M: MULTIPLY

D: DIVIDE

A: ADD

S: SUBTRACT

I was a little confused- so I hope it helped :')

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Quick anyone know the answer to this problem?
sweet-ann [11.9K]

Answer:

D

Step-by-step explanation:

Factor the numerators/ denominators

10 - 5 = 5(2a - 1) ← common factor of 5

4a² - 1 = (2a - 1)(2a + 1) ← difference of squares

[ Change ÷ to × and turn second fraction upside down ]

= \frac{2a+1}{5(2a-1)} × \frac{(2a-1)(2a+1)}{10a}

[ cancel the factor (2a - 1) on the numerator/denominator ] leaving

= \frac{(2a+1)^2}{5(10a)} = \frac{(2a+1)^2}{50a}

6 0
4 years ago
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Find the different quotient<br> f(x)=4x-7
bulgar [2K]

Answer:

4

Step-by-step explanation:

if its the difference quotient it is 4

Find  f ( x + h )  and  f ( x ) , and plug these values into the difference quotient formula.

ps can u mark me brainliest if i got it right plz

4 0
3 years ago
Linear inequalities<br> What is the solution to:<br> 4 + 8x &lt; -20
kvasek [131]

Answer:

x<-3

Step-by-step explanation:

4+8x<-20

4+8x-4<-20-4

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8x/8 < -24/8

x<-3

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3 years ago
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Find thd <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D" id="TexFormula1" title="\frac{dy}{dx}" alt="\frac{dy}{dx}" a
NARA [144]

x^3y^2+\sin(x\ln y)+e^{xy}=0

Differentiate both sides, treating y as a function of x. Let's take it one term at a time.

Power, product and chain rules:

\dfrac{\mathrm d(x^3y^2)}{\mathrm dx}=\dfrac{\mathrm d(x^3)}{\mathrm dx}y^2+x^3\dfrac{\mathrm d(y^2)}{\mathrm dx}

=3x^2y^2+x^3(2y)\dfrac{\mathrm dy}{\mathrm dx}

=3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}

Product and chain rules:

\dfrac{\mathrm d(\sin(x\ln y)}{\mathrm dx}=\cos(x\ln y)\dfrac{\mathrm d(x\ln y)}{\mathrm dx}

=\cos(x\ln y)\left(\dfrac{\mathrm d(x)}{\mathrm dx}\ln y+x\dfrac{\mathrm d(\ln y)}{\mathrm dx}\right)

=\cos(x\ln y)\left(\ln y+\dfrac1y\dfrac{\mathrm dy}{\mathrm dx}\right)

=\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}

Product and chain rules:

\dfrac{\mathrm d(e^{xy})}{\mathrm dx}=e^{xy}\dfrac{\mathrm d(xy)}{\mathrm dx}

=e^{xy}\left(\dfrac{\mathrm d(x)}{\mathrm dx}y+x\dfrac{\mathrm d(y)}{\mathrm dx}\right)

=e^{xy}\left(y+x\dfrac{\mathrm dy}{\mathrm dx}\right)

=ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}

The derivative of 0 is, of course, 0. So we have, upon differentiating everything,

3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}+\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}+ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}=0

Isolate the derivative, and solve for it:

\left(6x^3y+\dfrac{\cos(x\ln y)}y+xe^{xy}\right)\dfrac{\mathrm dy}{\mathrm dx}=-\left(3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}\right)

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}}{6x^3y+\frac{\cos(x\ln y)}y+xe^{xy}}

(See comment below; all the 6s should be 2s)

We can simplify this a bit by multiplying the numerator and denominator by y to get rid of that fraction in the denominator.

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^3+y\cos(x\ln y)\ln y-y^2e^{xy}}{6x^3y^2+\cos(x\ln y)+xye^{xy}}

3 0
3 years ago
Use DeMoivre's Theorem to find (3cis*pi/6)^3
Sonbull [250]

The correct value of (3cis(pi/6))³ is 27i.

<h3>What is Complex Number?</h3>

Complex numbers are numbers that consist of two parts — a real number and an imaginary number. Complex numbers are the building blocks of more intricate math, such as algebra.

Given the complex number in polar coordinate expressed as

z = r(cos∅+isin∅)

zⁿ =  {r(cos∅+isin∅)}ⁿ

According to DeMoivre’s Theorem;

zⁿ =  rⁿ(cosn∅+isinn∅)

Given the complex number;

(3cis(pi/6))³

= {3(cosπ/6 + isinπ/6)}³

Using  DeMoivre’s Theorem;

= 3³(cos3π/6 + isin3π/6)

=  3³(cosπ/2 + isinπ/2)

= 3³(0 + i(1))

= 27i

Thus, the correct value of (3cis(pi/6))³ is 27i.

Learn more about Complex number from:

brainly.com/question/10251853

#SPJ1

7 0
2 years ago
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